Java Http server demo

Java Http server demo

Import java. io. *; import java.net. *;/*** MyHttpServer implements a simple HTTP server that can obtain the content submitted by the user * and give the user a response * due to the time relationship, the processing of the http header is not standard **/public class MyHttpServer {// server root directory, post.html, upload.html are all placed in this location public static String WEB_ROOT = "c:/root "; // port private int port; // The url private String requestPath of the file requested by the user; // delimiter for post submission in mltipart/form-data mode, private String boundary = null; // The length of the body of the post request is private int. ContentLength = 0; public MyHttpServer (String root, int port) {WEB_ROOT = root; this. port = port; requestPath = null;} // process the GET request private void doGet (DataInputStream reader, OutputStream out) throws Exception {if (new File (WEB_ROOT + this. requestPath ). exists () {// find the file requested by the user under the root directory of the server and send it back to the browser InputStream fileIn = new FileInputStream (WEB_ROOT + this. requestPath); byte [] buf = new byte [fileIn. availabl E ()]; fileIn. read (buf); out. write (buf); out. close (); fileIn. close (); reader. close (); System. out. println ("request complete. ") ;}} // process the post request private void doPost (DataInputStream reader, OutputStream out) throws Exception {String line = reader. readLine (); while (line! = Null) {System. out. println (line); line = reader. readLine (); if ("". equals (line) {break;} else if (line. indexOf ("Content-Length ")! =-1) {this. contentLength = Integer. parseInt (line. substring (line. indexOf ("Content-Length") + 16);} // indicates that you want to upload an attachment and jump to the doMultiPart method. Else if (line. indexOf ("multipart/form-data ")! =-1) {// delimiter of multiltipart this. boundary = line. substring (line. indexOf ("boundary") + 9); this. doMultiPart (reader, out); return ;}// continue to read data submitted by normal post (no attachment) System. out. println ("begin reading posted data ...... "); String dataLine = null; // The post Data body sent by the user. byte [] buf ={}; int size = 0; if (this. contentLength! = 0) {buf = new byte [this. contentLength]; while (size
 
  
"; System. out. println (body); out. write (response. getBytes (); out. write (body. getBytes (); out. flush (); reader. close (); out. close (); System. out. println ("request complete. ");} // process the attachment private void doMultiPart (DataInputStream reader, OutputStream out) throws Exception {System. out. println ("doMultiPart ...... "); String line = reader. readLine (); while (line! = Null) {System. out. println (line); line = reader. readLine (); if ("". equals (line) {break;} else if (line. indexOf ("Content-Length ")! =-1) {this. contentLength = Integer. parseInt (line. substring (line. indexOf ("Content-Length") + 16); System. out. println ("contentLength:" + this. contentLength);} else if (line. indexOf ("boundary ")! =-1) {// obtain the multipart separator this. boundary = line. substring (line. indexOf ("boundary") + 9);} System. out. println ("begin get data ...... ");/* The comment below is the full text of a request with attachments sent by a browser. All Chinese characters are descriptive texts *****
  
   
...... Cache-Control: no-cache
   <这里有一个空行，表明接下来的内容都是要提交的正文>
    
----------------------------- 7d925132131f6
    <这是multipart分隔符>
     
Content-Disposition: form-data; name = "myfile"; filename = "mywork.doc" Content-Type: text/plain
     <附件正文>
      
........................................ ........................................ ......... ----------------------------- 7d925132131f6
      <这是multipart分隔符>
        Content-Disposition: form-data; name = "myname"
       <其他字段或附件> 
        <这里有一个空行> 
         <其他字段或附件的内容>
           ----------------------------- 7d925132131f6 --
          <这是multipart分隔符，最后一个分隔符多两个->
            **************************************** * ********************** // The comment above is of the multipart type with attachments. POST full-text model, * To remove the attachment, you must find the start position and end position of the attachment body. **/if (this. contentLength! = 0) {// read all submitted bodies, including attachments and other fields to buf. byte [] buf = new byte [this. contentLength]; int totalRead = 0; int size = 0; while (totalRead <this. contentLength) {size = reader. read (buf, totalRead, this. contentLength-totalRead); totalRead + = size;} // construct a String using buf. You can use the String to conveniently calculate the position of the attachment, String dataString = new String (buf, 0, totalRead); System. out. println ("the data user posted:/n" + dataString); int pos = dat AString. indexOf (boundary); // The Position of the first attachment is pos = dataString. indexOf ("/n", pos) + 1; pos = dataString. indexOf ("/n", pos) + 1; pos = dataString. indexOf ("/n", pos) + 1; pos = dataString. indexOf ("/n", pos) + 1; // start position of the attachment int start = dataString. substring (0, pos ). getBytes (). length; pos = dataString. indexOf (boundary, pos)-4; // The end position of the attachment. int end = dataString. substring (0, pos ). getBytes (). length; // locate fil Ename int fileNameBegin = dataString. indexOf ("filename") + 10; int fileNameEnd = dataString. indexOf ("/n", fileNameBegin); String fileName = dataString. substring (fileNameBegin, fileNameEnd);/*** sometimes the uploaded file displays the complete file name path, such as c:/my file/somedir/project.doc *. sometimes only the file name is displayed, such as myphoto.jpg. * therefore, you need to make a judgment. */If (fileName. lastIndexOf ("//")! =-1) {fileName = fileName. substring (fileName. lastIndexOf ("//") + 1);} fileName = fileName. substring (0, fileName. length ()-2); OutputStream fileOut = new FileOutputStream ("c: //" + fileName); fileOut. write (buf, start, end-start); fileOut. close (); fileOut. close ();} String response = ""; response + = "HTTP/1.1 200 OK/n"; response + = "Server: Sunpache 1.0/n "; response + = "Content-Type: text/html/n"; response + = "Last-Modified: Mon, 11 Jan 1998 13:23:42 GMT/n "; response + = "Accept-ranges: bytes"; response + = "/n"; out. write ("
           Test server
           
Post is OK
". GetBytes (); out. flush (); reader. close (); System. out. println ("request complete. ");} public void service () throws Exception {ServerSocket serverSocket = new ServerSocket (this. port); System. out. println ("server is OK. "); // enable serverSocket to wait for user requests to arrive, then process the request according to the request type. // here I only process GET and POST. // POST has the ability to parse a single attachment. while (true) {Socket socket = serverSocket. accept (); System. out. println (socket. getInetAddress (); System. out. println ("new request coming. "); DataInputStream reader = new DataInputStream (socket. getInputStream (); String line = reader. readLine (); String method = line. substring (0, 4 ). trim (); OutputStream out = socket. getOutputStream (); this. requestPath = line. split ("") [1]; System. out. println (method); if ("GET ". equalsIgnoreCase (method) {System. out. println ("do get ...... "); this. doGet (reader, out);} else if ("POST ". equalsIgnoreCase (method) {System. out. println ("do post ...... "); this. doPost (reader, out);} socket. close (); System. out. println ("socket closed. ") ;}} public static void main (String args []) throws Exception {MyHttpServer server = new MyHttpServer (" c:/root ", 8080); server. service ();}}