Java Judge 4 of the number within 10, through arithmetic to get 24

Please use Java to write a method to determine the given 4 digits, each value between 1~10, through +-*/operation, the result is 24, each number must be used and can only be used once.

The exhaustive method provided by netizens

public class T {


int[] can = new int[4];


public static void Main (string[] args) {


t tf = new T (3, 4, 5, 7);


System.out.println (Tf.getresult ());


　}


public T (int a, int b, int c, int d) {


can[0] = A;


can[1] = b;


can[2] = c;


can[3] = D;


　}


public String GetResult () {


double result1 = 0;


double result2 = 0;


double result3 = 0;


for (int i = 0; i < 4; i++) {


for (int j = 0; J < 4; + +) {


for (int k = 0; k < 4; k++) {


if (i!= j) {


result1 = Cal (Can[i], can[j], k);


for (int l = 0; l < 4; l++) {


for (int m = 0; m < 4; m++) {


if (i!= l && J!= L) {


result2 = Cal (Result1, Can[l], M);


for (int n = 0; n < 4; n++) {


for (int o = 0; o < 4; o++) {


if (i!= n && j!= n && l!= N) {


RESULT3 = Cal (Result2, can[n), O);


if (RESULT3 = = 24) {


return result (Can[i], K, Can[j], M, Can[l], O, can[n]);


　　　　　　　　　　　　}


　　　　　　　　　　　}


　　　　　　　　　　}


　　　　　　　　　}


　　　　　　　　}


　　　　　　　}


　　　　　　}


　　　　　}


　　　　}


　　　}


　　}


return null;


　}


private String result (int can1, int op1, int can2, int op2, int can3, int op3, int can4) {


Return "" + Can1 + CONVERT (OP1) + can2 + CONVERT (OP2) + can3 + CONVERT (OP3) + Can4;


　}


private String convert (int opr) {


if (OPR = = 0) {


return "+";


} else if (OPR = 1) {


return "-";


} else if (OPR = 2) {


return "*";


} else if (OPR = 3) {


return "/";


　　}


return "";


　}


private Double cal (double A, double b, int opr) {


if (OPR = = 0) {


return a + B;


} else if (OPR = 1) {


return a-b;


} else if (OPR = 2) {


return a * b;


} else if (OPR = 3) {


return a/b;


　　}


return 0;


　}


}

Operation result

3*4+5+7