Regular regular expressions have a powerful function in string processing, and sun has added support for it in jdk1.4
Here's a simple list of 4 common features:
Inquire:
String str= "ABC efg ABC";
String regex= "A|f"; Represents a or F
Pattern P=pattern.compile (regEx);
Matcher M=p.matcher (str);
Boolean rs=m.find ();
If there is a regex in Str, then RS is true, otherwise it is flase. If you want to ignore case when looking, you can write pattern p=pattern.compile (regex,pattern.case_insensitive);
Extraction:
String regex= ". +\\\\ (. +) $";
String str= "C:\\dir1\\dir2\\name.txt";
Pattern P=pattern.compile (regEx);
Matcher M=p.matcher (str);
Boolean rs=m.find ();
for (int i=1;i<=m.groupcount (); i++) {
System.out.println (M.group (i));
}
The above results are name.txt, and the extracted strings are stored in m.group (i), where I maximum is m.groupcount ();
Segmentation:
String regex= "::";
Pattern P=pattern.compile (regEx);
String[] R=p.split ("XD::ABC::CDE");
After execution, R is {"XD", "abc", "CDE"}, in fact, there are simple ways to split:
String str= "XD::ABC::CDE";
String[] R=str.split ("::");
Replace (delete):
String regex= "A +"; Represents one or more a
Pattern P=pattern.compile (regEx);
Matcher M=p.matcher ("aaabbced a Ccdeaa");
String S=m.replaceall ("A");
The result is "abbced A Ccdea"
If you write an empty string, you can achieve the deletion function, for example:
String S=m.replaceall ("");
The result is "bbced ccde"
Report:
\d equal to [0-9] numbers
\d is equal to [^0-9] not digital
\s is equal to [\t\n\x0b\f\r] blank character
\s is equal to [^ \t\n\x0b\f\r] non-blank character
\w is equal to [a-za-z_0-9] numbers or English characters.
\w is equal to [^a-za-z_0-9] non-numerals and English characters
^ represents the beginning of each line
$ indicates the end of each line
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