Java string asterisk, question mark matching problem solving method

Let's talk first. Number (the question mark is handled fairly simply)
Use a For loop to compare each.

* The processing of the number, it is more complicated. Here, I am using the left-fold idea to match. Because of my poor literature, it is not good to explain the code. Please take a look at the comments in the code. (although few, but key places have been written)

public class MyString {
String Str=null;
MyString (String value) {Str=value;}

public boolean islike (String regex)
{
if (Regex.indexof ("?")! =-1) return Wenhao (regex);
else if (Regex.indexof ("*")!=-1) return Xinghao (Str,regex);
return false;
}

Private Boolean Wenhao (String regex)
{
Match number
if (Str.length ()!=regex.length ()) return false;
for (int i=0;i<regex.length (); i++)
if (Str.charat (i)!=regex.charat (i) && Regex.charat (i)!= '? ')
return false;
return true;
}

Private Boolean Xinghao (String str,string regex)
{
* Number Matching
int Lstr=str.length ();
int Lreg=regex.length ();
int X1=regex.indexof ("*");
Switch (x1)
{
case-1:{
X1=-1 regex does not have the * number, does not need to fall to calculate
if (Lstr==lreg)
{
if (lstr==0) return true;
for (int kk=0;kk<lreg;kk++)//detect string match
if (Str.charat (KK)!=regex.charat (KK)) return false;
return true;
}else
return false;
}
Case 0:
{//x1=0 regex * number in the first place
if (lreg==1) return true;//only one asterisk, nature is matched, such as regex= "*"
Boolean right=false;
int = =;
* Number in the first place, locate the * number one
for (int k=0;k<lstr;k++)
if (Str.charat (k) ==regex.charat (x1+1) | | Regex.charat (x1+1) = = ' * ')
{p=k;right=true;break;} Encounter * * Directly right=true;
if (Right==false) return false;
Else
{
if (P==LSTR) return true;
Return Xinghao (str.substring (P,LSTR), regex.substring (X1+1,lreg));
}
}
Default
{//x1>0
for (int i=0;i<x1;i++)
if (Str.charat (i)!=regex.charat (i)) return false;
Return Xinghao (str.substring (X1,LSTR), regex.substring (X1,lreg));
}
}
}



public static void Main (string[] args) {

System.out.println ("Str=abcd regex=abc?:" +new myString ("ABCD"). Islike ("ABC?");
System.out.println ("Str=abcd regex=a???:" +new myString ("ABCD"). Islike ("A???"));
System.out.println ("Str=abcd regex=a??:" +new myString ("ABCD"). Islike ("A??"));
System.out.println ("Str=abcd regex=?") Bc? : "+new myString (" ABCD "). Islike ("? BC? "));
System.out.println ("Str=abcd regex=*b*d:" +new myString ("ABCD"). Islike ("*b*d"));
System.out.println ("Str=abcd regex=*bcd:" +new myString ("ABCD"). Islike ("*BCD"));
System.out.println ("Str=abcd regex=*a*b*d:" +new myString ("ABCCD"). Islike ("*a*b*d"));

}

}