JavaScript array de-weight method summary

Source: Internet
Author: User
Tags javascript array hasownproperty

1. Using the properties of arrays

1. Iterate through the array, and also traverse the auxiliary array to find out whether there are the same items in the two arrays, and then push in if there is a break.

  

//first version array de-weightfunctionUnique (arr) {varres =[], Len=arr.length;  for(Let i = 0;i < Len; i++){        varReslen =res.length;  for(Let J = 0;j < Reslen; j + +) {//traversing auxiliary Arrays            if(Arr[i] = = =Res[j]) {                 Break; }        }        if(J = =Reslen) {Res.push (arr[i]);//No, add it in .        }    }    returnRes;}

  

2. Using Es5 's IndexOf method

// the second version of the array to ES5 syntax, IE8 can not be used function Unique (arr) {    var len = arr.length,        = [];      for (Let i = 0; i < len; i++) {        = arr[i];         if // no Return-1 found             Res.push (Arr[i]);        }    }     return Res;}

  

3. If the array is already sorted

function Unique (arr) {    var len = arr.length;        Last,        = [];      for (Let i = 0;i < Len; i++) {        = arr[i];         if // Store the last value             Res.push (val);        }         = val;    }     return Res;}

  

4. Leave an interface and pass a parameter to determine if the array is already sorted

functionUnique (arr, issort) {varLen =Arr.length, Res=[], last; if(Issort!== ' Boolean ') {Issort=false; }     for(Let i = 0;i < Len; i++){        varval =Arr[i]; if(issort) {if(!i | | val!==Last )            {Res.push (val); } Last=Val; }Else{            if(Res.indexof (val) = = = 1) {Res.push (val); }        }    }    returnRes;}

5. If there is a special need, leave an interface, more flexible

functionUnique (arr, Issort, fn) {varres =[], Len=Arr.length, NewArr=[], last;  for(Let i = 0;i < Len; i++){        varval =arr[i], com= fn?fn (Val, I, arr): Val; if(issort) {if(!i | | com = = =Last )            {Res.push (val); } Last=com; }Else if(FN) {if(Newarr.indexof (com) = = = 1) {Newarr.push (COM);            Res.push (Val); }        }Else if(Res.indexof (val = = = 1) {Res.push (val); }    }    returnRes;}

6. Optimize with internal filter method

function Unique (arr) {    var res = [],    = Arr.filter (function(item, index, arr) {         return res.indexof (item) = = = Index;  // returns True if added to the array res, otherwise not added     });     return Res;}

2. Use of object properties

1. The first method

function Unique (arr) {    var obj = {},        = [],    = Arr.filter (function  (item, index, AEE) {        returnfalsetrue);    });     return Res}

Note: There is a bug,var = [1, 1, "1", 2], the number type is not recognized, and the string type is added to the object and is converted to a string.

2. The second method

 

function Unique (arr) {    var obj = {},        = [],        = arr.length;     = Arr.filter (function  (item, index, arr) {        return obj.hasownproperty (  typeoffalse : (typeoftrue;      });     return Res;}

Note: There are also bugs here, because the return type of typeof does not detect the object.

3. The third method

Use the JSON method to optimize.

function Unique (arr) {    var obj = {},        = [],        = arr.length;     = Arr.filter (function  (item, index, arr) {        return obj.hasownproperty (  typeoffalse : (typeoftrue;    })     return Res;}
The set () object in 3.ES6
function Unique (arr) {    return [... New Set (arr)];}

JavaScript array de-weight method summary

Related Article

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.