Javascript-how to notify IOS and Android apps to jump to the corresponding page on a webpage

In this case, you can open a third-party lottery page in the app and enter only one link to the place where you receive the prize. My own page should also be opened in the app. Then, how can I close the page and notify the APP? go to the desired interface? Give the keyword or implementation method .. For help, you can open a third-party lottery page in the app and enter only one link to the place where you receive the prize. My own page should also be opened in the app. Then, how can I close the page and notify you? what interface does the APP go? Give the keyword or implementation method .. Help

Reply content:

In this case, you can open a third-party lottery page in the app and enter only one link to the place where you receive the prize. My own page should also be opened in the app. Then, how can I close the page and notify the APP? go to the desired interface? Give the keyword or implementation method .. Help

Set a response protocol in the App, preferably different fromHttpFor example, defineAbcProtocol listener. When a webpage is linkedAbc: // xxxThe system automatically opens the App and submits the address to the App for processing. At this time, the App can perform corresponding operations by identifying the parameters in the address.

Generally, a protection page needs to be created after the page, that is, if the user does not install the App or the browser does not support it (the third-party browser may not support it) instead of closing the page.

Keywords: webpage opening App there are many related technical tutorials

If it is me, We will intercept it in shouldOverrideUrlLoading of webviewclient.