Here's how to get the IndexOf function in JavaScript to ignore the case.
Change them all to uppercase or lowercase, and compare them.
This is a relatively simple approach!
IndexOf the character position of the substring for the first time within the object.
Use toLowerCase or toUpperCase code as follows:
<script> var teststr = ' ABCDEF '; var subStr = ' BCD '; Alert (Teststr.tolowercase (). IndexOf (Substr.tolowercase ())); Teststr = ' AbCdEf '; Alert (Teststr.tolowercase (). IndexOf (Substr.tolowercase ())); </script>
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Or look at how the following is extended for the IndexOf function:
<script> String.prototype.indexOf = function (f,m) {var mm = (M = = False)? "I": ""; var re = eval ("/" + F + "/" +mm); var RT = This.match (re); return (RT = null)? -1:rt.index; var test = "Absnegkiugfkalg"; Alert (Test.indexof ("Kiu", false)); </script>
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The following compatible original IndexOf function allows you to add indexof functions that are directly used to ignore the case of JavaScript.
<script language= "JavaScript" > String.prototype._indexof = String.prototype.indexOf; String.prototype.indexOf = function () {if (typeof (Arguments[arguments.length-1))!= ' Boolean ' return THIS._INDEXOF.A Pply (this,arguments); else {var bi = arguments[arguments.length-1]; var thisobj = this; var idx = 0; if (typeof (Arguments[arguments.length-2]) = = ' number ') {idx = arguments[arguments.length-2]; Thisobj = this.substr (idx); var re = new RegExp (arguments[0],bi? ') I ': '); var r = Thisobj.match (re); return r==null?-1:r.index + idx; } alert ("Bcssssasdfsdf". IndexOf (' A ', 3,true)); Alert ("Bcssssasdfsdf". IndexOf (' A ', 3)); </script>
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