JavaScript Precision Subtraction

In a recent project to use JS to realize the function of automatic calculation, this thought just to achieve simple addition, subtraction, multiplication, except on it, so rinsed finished.

Just when I was happy, I found the problem ...

When doing some floating-point arithmetic, the calculation results are let me surprise ah, that value let me laugh and cry, a long list of values, too cow ...

I was wondering!! But fortunately a lot of cattle, gave me a solution, hey ... The problem basically solved, in order to express the feeling, I decided to put the code out, we share, hope to give some people some help.

JS Code

2. addition function
4. function Accadd (arg1, arg2) {
6. var r1, R2, M;
8. try {
10. R1 = Arg1.tostring (). Split (".")  [1].length;
12. }
14. catch (e) {
16. R1 = 0;
18. }
20. try {
22. r2 = arg2.tostring (). Split (".")  [1].length;
24. }
26. catch (e) {
28. r2 = 0;
30. }
32. m = Math.pow (Ten, Math.max (R1, r2));
34. return (ARG1 * m + arg2 * m)/m;
36. }
38. Add an Add method to the number type, which is used directly with. Add to complete the calculation.
40. Number.prototype.add = function (ARG) {
42. return Accadd (ARG, this );
44. };
48. Subtraction function
50. function Subtr (arg1, arg2) {
52. var r1, R2, M, N;
54. try {
56. R1 = Arg1.tostring (). Split (".")  [1].length;
58. }
60. catch (e) {
62. R1 = 0;
64. }
66. try {
68. r2 = arg2.tostring (). Split (".")  [1].length;
70. }
72. catch (e) {
74. r2 = 0;
76. }
78. m = Math.pow (Ten, Math.max (R1, r2));
80. //last Modify by Deeka
82. //Dynamic control accuracy length
84. n = (r1 >= r2)? R1:R2;
86. return ((ARG1 * M-ARG2 * m)/m). ToFixed (n);
88. }
92. Add an Add method to the number type, and use the. Sub directly to complete the calculation.
94. Number.prototype.sub = function (ARG) {
96. return SUBTR (this, ARG);
98. };
102. multiplication function
104. function Accmul (arg1, arg2) {
106. var m = 0, S1 = arg1.tostring (), S2 = arg2.tostring ();
108. try {
110. M + = S1.split (".")  [1].length;
112. }
114. catch (e) {
116. }
118. try {
120. M + = S2.split (".")  [1].length;
122. }
124. catch (e) {
126. }
128. return Number (S1.replace (".", "")) * Number (S2.replace (".", "")) /Math.pow (ten, M);
130. }
132. Add a Mul method to the number type and use it directly with the. Mul to complete the calculation.
134. Number.prototype.mul = function (ARG) {
136. return Accmul (ARG, this );
138. };
142. Division function
144. function Accdiv (arg1, arg2) {
146. var t1 = 0, t2 = 0, R1, R2;
148. try {
150. T1 = arg1.tostring (). Split (".")  [1].length;
152. }
154. catch (e) {
156. }
158. try {
160. T2 = arg2.tostring (). Split (".")  [1].length;
162. }
164. catch (e) {
166. }
168. With (Math) {
170. R1 = number (arg1.tostring (). Replace (".", ""));
172. r2 = number (arg2.tostring (). Replace (".", ""));
174. return (R1/R2) * POW (T2-T1);
176. }
178. }
180. Add a div method to the number type, and use the. Div directly to complete the calculation.
182. Number.prototype.div = function (ARG) {
184. return Accdiv (this, ARG);
186. };

Addition functions function Accadd (arg1, arg2) {var r1, R2, m;try {r1 = arg1.tostring (). Split (".") [1].length;} catch (e) {r1 = 0;} try {r2 = arg2.tostring (). Split (".") [1].length;} catch (e) {r2 = 0;} m = Math.pow (Ten, Math.max (R1, r2)); return (ARG1 * m + arg2 * m)/m;} Add an Add method to the number type, which is used directly with. Add to complete the calculation. Number.prototype.add = function (ARG) {return Accadd (ARG, this);};/ /subtraction Functions function Subtr (arg1, arg2) {var r1, R2, M, n;try {r1 = arg1.tostring (). Split (".") [1].length;} catch (e) {r1 = 0;} try {r2 = arg2.tostring (). Split (".") [1].length;} catch (e) {r2 = 0;}     m = Math.pow (Ten, Math.max (R1, r2)); Last modify by Deeka//dynamic control accuracy length n = (r1 >= r2)? R1:r2;return ((arg1 * M-ARG2 * m)/m). ToFixed (n);} Add an Add method to the number type, and use the. Sub directly to complete the calculation. Number.prototype.sub = function (ARG) {return SUBTR (this, arg);};/ /multiplication Functions function Accmul (arg1, arg2) {var m = 0, S1 = arg1.tostring (), S2 = arg2.tostring (), try {m + = S1.split (".") [1].length;} catch (e) {}try {m + = S2.split (".") [1].length;} catch (e) {}return NumbeR (S1.replace (".", "")) * Number (S2.replace (".", ""))/Math.pow (ten, M);} Add a Mul method to the number type and use it directly with the. Mul to complete the calculation. Number.prototype.mul = function (ARG) {return Accmul (ARG, this);}; The Division functions function Accdiv (arg1, arg2) {var t1 = 0, t2 = 0, r1, r2;try {t1 = arg1.tostring (). Split (".") [1].length;} catch (e) {}try {t2 = arg2.tostring (). Split (".") [1].length;} catch (E) {}with (Math) {r1 = number (arg1.tostring (). Replace (".", "")); r2 = number (arg2.tostring (). Replace (".", "")); Return (R1/R2) * POW (ten, T2-t1);}} Add a div method to the number type, and use the. Div directly to complete the calculation.  Number.prototype.div = function (ARG) {return Accdiv (this, arg);};

How to use:

JS Code

2. Examples of additions (others are similar)
4. function Calculate () {
6. //Number 1
8. var num1 = 10;
10. //Number 2
12. var num2 = 5;
14. //Calculate NUM1 + num2
16. Alert (Num1.add (num2));
18. }

The addition example (others are similar) function calculate () {//number 1                var num1 = ten;                Number 2                var num2 = 5;                Calculate NUM1 + num2                alert (Num1.add (num2));}

JavaScript Precision Subtraction