JavaScript time difference calculation function code instance

JavaScript time difference calculation function code instance

<script language= "JavaScript" >

Date.prototype.dateDiff = function (interval,objdate) {

If the parameters are insufficient or the objdate is not a Date object, it is returned undefined

if (arguments.length<2| | Objdate.constructor!=date) return undefined;

Switch (interval) {

Calculate the second difference

Case "S": Return parseint ((objdate-this)/1000);

Calculation of Difference

Case "n": Return parseint ((objdate-this)/60000);

Calculate the time difference

Case "H": Return parseint ((objdate-this)/3600000);

Calculate the day difference

Case "D": Return parseint ((objdate-this)/86400000);

Calculate the week difference

Case "W": Return parseint ((objdate-this)/(86400000*7));

Calculate the month difference

Case "M": Return (Objdate.getmonth () +1) + ((Objdate.getfullyear ()-this.getfullyear ()) *12)-(This.getmonth () +1);

Calculate the Year Difference

Case "Y": Return Objdate.getfullyear ()-this.getfullyear ();

The input is misunderstood

Default:return undefined;

}

}

</script>

The example of calling this method is as follows:

<script language= "JavaScript" >

var SDT = new Date ("2004/05/20 07:30:00");

var EDT = new Date ("2005/05/20 08:32:02");

Document.writeln ("Seconds Difference:" +sdt.datediff ("s", EDT) + "<br>");

Document.writeln ("Spread:" +sdt.datediff ("n", EDT) + "<br>");

Document.writeln ("Time Difference:" +sdt.datediff ("H", EDT) + "<br>");

Document.writeln ("Day Difference:" +sdt.datediff ("D", EDT) + "<br>");

Document.writeln ("Week Difference:" +sdt.datediff ("W", EDT) + "<br>");

Document.writeln ("Month Difference:" +sdt.datediff ("M", EDT) + "<br>");

Document.writeln ("Year Difference:" +sdt.datediff ("Y", EDT) + "<br>");

</script>

<script>

var S1 = "2009/08/01";

var s2 = "2009/12/31";

S1 = new Date (S1);

S2 = new Date (s2);

var time= s2.gettime ()-s1.gettime ();

var days = parseint (Time/(1000 * 60 * 60 * 24));

Alert ("Days difference:" + day);

</script>

JavaScript calculates the time difference

<script>

var startdate= new Date ("2004/3/1 12:00");

var enddate= new Date ("2004/3/1 15:00");

var df= (Enddate.gettime ()-startdate.gettime ())/1000/3600;

Alert (df+ "hour");

</script>

<script language= "JavaScript" >

<!--

var st1 = "2009/8/25 19:35";

var st2 = "2009/8/25 19:28";

var time1 = new Date (ST1);

var tiem2 = new Date (ST2);

var days = (Time1.gettime ()-tiem2.gettime ())/1000/60;//min

alert (days);

Document.writeln (days);

-

</SCRIPT>

Ask for the time difference between two date subtraction with JavaScript!

var oldtime=date.parse ("2005-1-10 8:00:00");

var newtime=date.parse ("2005-1-11 12:00:00");

var diff = newtime-oldtime, get millisecond difference, convert to hours

Who can tell me how to convert the string: "2005-1-12 8:00:00" to a datetime type!

var str= "2005-1-12 8:00:00";

var arr=str.split ("");

var arr1=arr[0].split ("-");

var arr2=arr[1].split (":");

Note that the six parameters in the new date () are month and day, and the months start at 0,

var date=new date (arr1[0],arr1[1],arr1[2],arr2[0],arr2[1],arr2[2]);

Get current time

var now =new Date ();

var year = Now.getfullyear ();

var month = Now.getmonth () +1;

var day = Now.getdate ();

var hour = now.gethours ();

var minute = Now.getminutes ();

var second = Now.getseconds ();

JavaScript time difference calculation function code instance