Wx.getlocation ({
type: 'wgs84', // 默认为wgs84的gps坐标,如果要返回直接给openLocation用的火星坐标,可传入'gcj02' success: function (res) { var latitude = res.latitude; // 纬度,浮点数,范围为90 ~ -90 var longitude = res.longitude; // 经度,浮点数,范围为180 ~ -180。 var speed = res.speed; // 速度,以米/每秒计 var accuracy = res.accuracy; // 位置精度 $.ajax({ url:"{:U('home/Share/index')}", data:{latitude:latitude,longitude:longitude}, type:"POST", dataType:"json", success:function(){ } }) },})
So with the Ajax value in the background controller,var_dump ($_post) is a null value, what is going on?
Reply content:
Wx.getlocation ({
type: 'wgs84', // 默认为wgs84的gps坐标,如果要返回直接给openLocation用的火星坐标,可传入'gcj02' success: function (res) { var latitude = res.latitude; // 纬度,浮点数,范围为90 ~ -90 var longitude = res.longitude; // 经度,浮点数,范围为180 ~ -180。 var speed = res.speed; // 速度,以米/每秒计 var accuracy = res.accuracy; // 位置精度 $.ajax({ url:"{:U('home/Share/index')}", data:{latitude:latitude,longitude:longitude}, type:"POST", dataType:"json", success:function(){ } }) },})
So with the Ajax value in the background controller,var_dump ($_post) is a null value, what is going on?
The wording is correct, as to why you need to debug your code if you don't get it.
Meat testing Methods:
The direct output receives the data, and then the success
returned object is accepted.
后台输出:echo json_encode($_POST);exit();前台输出:success:function(msg){ console.log(msg); }
Ajax is an asynchronous request and cannot be output directly from the controller