JQuery jump out of each loop method

Source: Internet
Author: User

JQuery jumps out of each loop without using break and continue, to use return,

Break----with return false;

Continue--use return ture;

The code is as follows Copy Code
$.each (Array,function () ... {
if (condition 1 set up) ... {
return true; equivalent to continue;
}
if (condition 2 set up) ... {
return false; equivalent to a break;
}
});

Specifically as follows

Example 1

Jump out of the entire loop, break function

The code is as follows Copy Code
$ (". Test"). each (function (i) {

if (i==3) {
return false;
}
alert (i);
});

Example 2.

Jump out of this cycle, into the next cycle, continue function

The code is as follows Copy Code
$ (". Test"). each (function (i) {

if (i==3) {
return true;
}
alert (i);
});

The answer is to use return false; Remember oh, not using break, nor directly using return;

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