Js BigDecimal method of realizing precise subtraction operation

An addition function that is used to obtain accurate addition results
function Accadd (arg1, arg2) {
var r1, R2, M, C;
try {
R1 = Arg1.tostring (). Split (".") [1].length;
} catch (e) {
R1 = 0;
}
try {
r2 = arg2.tostring (). Split (".") [1].length;
} catch (e) {
r2 = 0;
}
c = Math.Abs (R1-R2);
m = Math.pow (Ten, Math.max (R1, r2));
if (C > 0) {
var cm = Math.pow (ten, C);
if (R1 > R2) {
Arg1 = number (arg1.tostring (). Replace (".", ""));
arg2 = number (arg2.tostring (). Replace (".", "")) cm;
} else {
Arg1 = number (arg1.tostring (). Replace (".", ""))cm
arg2 = number (arg2.tostring (). Replace (".", ""));
}
} else {
Arg1 = number (arg1.tostring (). Replace (".", ""));
arg2 = number (arg2.tostring (). Replace (".", ""));
}
Return (arg1 + arg2)/m;
}

/** * * Subtraction function, used to get accurate subtraction results * * Description: JavaScript subtraction results will be error, when the two floating-point subtraction will be more obvious. This function returns a more accurate subtraction result.    * * Call: Accsub (ARG1,ARG2) * * return value: arg1 The exact result of subtracting arg2 **/function accsub (arg1, arg2) {var r1, R2, M, N; try {r1 = arg1.tostring (). Split (".")    [1].length;    } catch (e) {r1 = 0; try {r2 = arg2.tostring (). Split (".")    [1].length;    } catch (e) {r2 = 0; } m = Math.pow (Ten, Math.max (R1, r2)); Last modify by Deeka//dynamic control accuracy length n = (r1 >= r2)?    R1:R2; Return ((ARG1 * M-ARG2 * m)/m). ToFixed (n);} /** * * Multiplication function, used to get accurate multiplication results * * Description: JavaScript multiplication results will be error, when the two floating point multiplied by the more obvious. This function returns a more accurate multiplication result. * * Call: Accmul (ARG1,ARG2) * * return value: Arg1 times the exact result of Arg2 **/function Accmul (arg1, arg2) {var m = 0, S1 = arg1.tostring (), S2 =    Arg2.tostring (); try {m + = S1.split (".")    [1].length; } catch (e) {} try {m + = S2.split (".")    [1].length; } catch (e) {} return Number (S1.replace (".", "")) * Number (S2.replace (".", ""))/Math.pow (m);} /** * * Division LetterNumber, used to get accurate division results * * Description: JavaScript division results will be error, when the two floating point number is more obvious when dividing. This function returns a more accurate division result.    * * Call: Accdiv (ARG1,ARG2) * * return value: Arg1 divided by arg2 exact result **/function accdiv (arg1, arg2) {var t1 = 0, t2 = 0, R1, R2; try {t1 = arg1.tostring (). Split (".")    [1].length; } catch (e) {} try {t2 = arg2.tostring (). Split (".")    [1].length;        } catch (e) {} with (Math) {r1 = number (arg1.tostring (). Replace (".", ""));        r2 = number (arg2.tostring (). Replace (".", ""));    Return (R1/R2) * POW (T2-T1); }}

Js BigDecimal How to achieve accurate subtraction operations