JS: Deep function (function is Object)

Source: Internet
Author: User

Since the function is an object, you can pass the function directly through the arguments, or you can use the function as the return value.
function Calfun (fun,arg) {
The first argument is a function object
return Fun (ARG);

function sum (num) {
return num+100;

function say (str) {
Alert ("Hello" +str);
Called the Say function
Callfun (say, "JS"); Hello JS
The SUM function is called
Alert (Callfun (sum,100)); 200

function Fun1 (ARG) {
var rel = function (num) {
return arg+num;
return rel;
}//Returns a function object
F is a function object that can complete the invocation
var f = fun1 (20);
alert (f); function (num) {return arg+name;}
Alert (f (30)); 50

var arr = [1,2,33,12,198];
Arr.sort ();
Alert (arr); 1,12,198,33 for JS, the default is to sort by string.

If we want to sort by number size, you can do this by:
function Sortbynum (A, b) {
Return parseint (a)-parseint (b);
Arr.sort ();
Alert (arr); 1,2,12,33,198

Sort by Object
function Person (name,age) {

var p1 = new Person ("John", 23);
var p2 = new Person ("Lemo", 39);
var p3 = new Person ("Ada", 41);

var PS = [P1,P2,P3];

Ps.sort (Sortbyage);
Ps.sort (Sortbyproperty ("Age"));

function Sortbyname (obj1,obj2) {
Return obj1.name>obj2.name?1: (obj1.name==obj2.name?0:-1);
}//Sort by name
function Sortbyage (obj1,obj2) {
return obj1.age-obj2.age;
}//Sort by age

The problem with this approach to sorting is the need to create a function for each attribute, which is obviously inflexible
But it is not the same if you call through the function's return value.
function Sortbyproperty (PropertyName) {
var sortfun = function (obj1,obj2) {
Return obj1[propertyname]>obj2[propertyname]?1: (obj1[propertyname]==obj2[propertyname]?0:-1);
return sortfun;

original articles such as reproduced, please indicate the source, this article started in CSDN website: http://blog.csdn.net/magneto7/article/details/24724299

JS: Deep function (function is Object)

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