JS Get URL Multiple parameters

function GetQueryString(name) {       var reg = new RegExp( "(^|&)" + name + "=([^&]*)(&|$)" );       var r = window.location.search.substr(1).match(reg);       if (r!= null ) return unescape(r[2]); return null ; } // 调用方法 alert(GetQueryString( "参数名1" )); alert(GetQueryString( "参数名2" )); alert(GetQueryString( "参数名3" ));Cases:

If the Address bar URL is:abc.html?id=123&url=http://www.maidq.com

So, but you use the above method to invoke: Alert (getquerystring ("url"));

A dialog box pops up: The content is http://www.maidq.com

If using: Alert (getquerystring ("id")), then the popup content is 123;

Of course, if you do not pass parameters, such as your address is abc.html back no parameters, the force output call results sometimes error:

So we have to add a judgment to determine if the argument we requested is empty, first assign the value to a variable:

var myurl=GetQueryString( "url" ); if (myurl != null && myurl.toString().length>1) {     alert(GetQueryString( "url" )); }

This will not be an error!

Reference: http://www.cnblogs.com/fishtreeyu/archive/2011/02/27/1966178.html

JS Get URL Multiple parameters