The scope of JavaScript has always been the front-end development of the more difficult to understand the knowledge point, for the scope of JavaScript mainly remember a few words, go all over the world are not afraid of ...
One, "no block-level scope in JavaScript"
There is a block-level scope in Java or C #, which is: curly braces are also a scope.
Public Static void Main () { if(1==1) { = "Seven"; } SYSTEM.OUT.PRINTLN (name);} // Error
Java
Public Static void Main () { if(1= =1) {string"Seven "; } Console.WriteLine (name);} // Error
C #
No block-level scopes in the JavaScript language
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function main () {      if (1==1) { var name = ' seven '           console.log (name); //output: Seven |
Add: The title adds double quotes because the LET keyword is introduced in JavaScript6 to specify that the variable belongs to a block-level scope.
Second, JavaScript uses function scope
In JavaScript each function acts as a scope, and the variables in the internal scope cannot be accessed externally.
function Main () { var innervalue = ' Seven ';} Main (); Console.log (Innervalue); Error: Uncaught referenceerror:innervalue is not defined
Third, the scope chain of JavaScript
Because each function in JavaScript acts as a scope, the scope chain appears if function nesting functions occur.
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xo =
‘alex‘
;
function
Func(){
var
xo =
"seven"
;
function
inner(){
var
xo =
‘alvin‘
;
console.log(xo);
}
inner();
}
Func();
|
As shown above, there are three scopes of scope chain, if the scope chain, then the search for variables will appear in order, for the above example:
When executing Console.log (XO), its search order is based on the scope of the chain from the inside to the outside of the priority, if the inner layer does not step up to find, until the throw exception is not found.
Iv. The scope chain of JavaScript was created before execution
The scope of JavaScript is created before it is executed, and it is only necessary to follow the scope chain to find out when to execute it later.
Example one:
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xo =
‘alex‘
; function
Func(){
var
xo =
"seven"
;
function
inner(){
console.log(xo);
}
return
inner;
}
var
ret = Func();
ret();
// 输出结果: seven
|
The above code, before the function is called, the scope chain already exists:
- Global scope, Func function scope, inner function scope
When performing ret (); , since its surrogate refers to the inner function, the scope chain of this function has been defined before execution: global scope, Func function scope, and inner function scope, so, in the execution of RET (); , the variable is searched based on the scope chain that already exists.
Example two:
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xo =
‘alex‘
;
function
Func(){
var
xo =
"eirc"
;
function
inner(){
console.log(xo);
}
xo =
‘seven‘
;
return
inner;
}
var
ret = Func();
ret();
// 输出结果: seven
|
The code above is the same as example one, and it also emphasizes that the scope chain already exists before the function is called:
- Global scope, Func function scope, inner function scope
Different when executing var ret = Func (); , the value of the XO variable in the func scope has been reset from "Eric" to "seven", so the RET () is then executed; , you can only find "seven".
Example three:
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xo =
‘alex‘
;<br>
function
Bar(){
console.log(xo);
}
function
Func(){
var
xo =
"seven"
;
return
Bar;
}
var
ret = Func();
ret();
// 输出结果: alex
|
The code above has created two scope chains before the function is executed:
- global scope, bar function scope
- Global scope, Func function scope
When performing ret (); , the bar function is referred to as RET, and the scope chain of the bar function already exists: global scope and bar function scope, so execution will be based on the existing scope chain to find.
V. Declaration of Advance
In JavaScript, if you do not create a variable and go directly to it, the error is:
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console.log(xxoo); // 报错:Uncaught ReferenceError: xxoo is not defined |
If you create a value without assigning a value in JavaScript, the value is undefined, such as:
123 |
var xxoo; console.log(xxoo); // 输出:undefined |
Within the function, if you write this:
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function Foo(){ console.log(xo); var xo = ‘seven‘ ; } Foo(); // 输出:undefined |
The above code, not error, but output undefined, the reason is: the JavaScript function before it is executed, the variables are all declared, without assigning value. Therefore, the equivalent of the above example, the function in "precompiled" when the Var XO has been executed, so the above code output is undefined.
JS Scope just a few words