# [Leedcode 129] Sum Root to Leaf Numbers

Source: Internet
Author: User

Given a binary tree containing digits from only `0-9` , each root-to-leaf path could represent a number.

An example is the Root-to-leaf path `1->2->3` which represents the number `123` .

Find The total sum of all root-to-leaf numbers.

For example,

`    1   /   2   3`

The Root-to-leaf path `1->2` represents the number `12` .
The Root-to-leaf path `1->3` represents the number `13` .

Return the sum = + = `25` .

`/*** Definition for a binary tree node. * public class TreeNode {* int val; * TreeNode left; * TreeNode rig Ht * TreeNode (int x) {val = x;} }*/ Public classSolution {//the path from the root node to the leaf node represents a numeric value that finds all of these values and then accumulates a sum. DFS//The main point of attention to the parameters of the Getres function, path represents the arrival node, the path already exists on the and! //Note Test instructions: only reach the leaf node (left=right=null) can save the results to res, so pay attention to the recursive end condition    intRes;  Public intsumnumbers (TreeNode root) {getres (root,0); returnRes; }     Public voidGetres (TreeNode node,intPath) {//Note the meaning of the path parameter!         if(node==NULL)return; inttemp=path*10+Node.val; if(node.left==NULL&&node.right==NULL) {res+=temp; return;        } getres (Node.left,temp);            Getres (node.right,temp); }}`

[Leedcode 129] Sum Root to Leaf Numbers

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