LeetCode 165 Compare Version Numbers (comparison Version) (string )(*)

LeetCode 165 Compare Version Numbers (comparison Version) (string )(*)
Translation

Compare two versions: version1 and version2. If version1 is greater than version2, 1 is returned. If version1 is less than version2,-1 is returned. Otherwise, 0 is returned. You can assume that the version number string is not empty and only contains numbers and "." characters. The "." character is used to separate numeric sequences instead of decimal vertices. For example, 2.5 is neither a "Two Half" nor a "half to three", but the fifth minor version in the second version. Here is an example of version number sorting: 0.1 <1.1 <1.2 <13.37

Original

Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.You may assume that the version strings are non-empty and contain only digits and the . character.The . character does not represent a decimal point and is used to separate number sequences.For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.Here is an example of version numbers ordering:0.1 < 1.1 < 1.2 < 13.37

Analysis

I was also complacent when I saw this question, because the idea was ready immediately, ......

What I think of is to cut the string according to ".", then convert the number from string to int and save it to the vector, and finally compare the data in the vector.

But I didn't expect such abnormal test cases ......

"19.8.3.17.5.01.0.0.4.0.0.0.0.0.0.0.0.0.0.0.0.0.00.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.000000.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.000000""19.8.3.17.5.01.0.0.4.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0000.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.000000"

Then I got down ......

Below is the code for converting string to vector, which is used only for personal notes ......

vector
  
    getVersionVector(string version) {    vector
   
     versionV;    istringstream sstream(version);    string temp;     while (!sstream.eof()) {        getline(sstream, temp, '.');        versionV.push_back(stoi(temp));    }                           return versionV;}
   
  

Let's take a look at other people's code and try again next time!

class Solution {public:    int compareVersion(string version1, string version2) {        istringstream s1(version1), s2(version2);        string a, b;        while (!s1.eof() && !s2.eof())        {            getline(s1, a, '.');            getline(s2, b, '.');            if (stoi(a) == stoi(b)) continue;            else return stoi(a) > stoi(b) ? 1 : -1;        }        if (s1.eof() && s2.eof()) return 0;        if (s1.eof())        {            while (!s2.eof())            {                getline(s2, b, '.');                if (stoi(b) != 0) return -1;            }        }        if (s2.eof())        {            while (!s1.eof())            {                getline(s1, a, '.');                if (stoi(a) != 0) return 1;            }        }        return 0;    }};

class Solution {public:    int compareVersion(string version1, string version2) {        size_t b1 = 0, i1 = 0, b2 = 0, i2 = 0;        while (i1 < version1.size() || i2 < version2.size()) {            while (i1 < version1.size() && version1[i1] != '.') ++i1;            while (i2 < version2.size() && version2[i2] != '.') ++i2;            string sub1 = (i1 == b1) ? "0" : version1.substr(b1, i1);            string sub2 = (i2 == b2) ? "0" : version2.substr(b2, i2);            int ii1 = stoi(sub1), ii2 = stoi(sub2);            if (ii1 > ii2) return 1;            else if (ii1 < ii2) return -1;            else {                b1 = (b1 == i1) ? i1 : (i1++) + 1;                b2 = (b2 == i2) ? i2 : (i2++) + 1;            }        }        return 0;    }};

int compareVersion(string version1, string version2) {    istringstream v1(version1+"."), v2(version2+'.');    char dot = '.';    int val1 = 0, val2 = 0;    while (true) {        void* p1 = (v1>>val1>>dot), *p2= (v2>>val2>>dot);        if (! p1 && !p2)            return 0;        if (! p1)             val1 = 0;        if (! p2)            val2 = 0;        if (val1>val2)            return 1;        else if (val1