[Leetcode] 243. Shortest word Distance shortest word distance

Source: Internet
Author: User

Given a list of words and words word1 and Word2, return the shortest distance between these the word s in the list.

For example,
Assume that words = ["practice", "makes", "perfect", "coding", "makes"] .

Given word1 = “coding” , word2 = “practice” , return 3.
Given word1 = "makes" , word2 = "coding" , return 1.

Note:
Assume that word1 does not equal to word2, and Word1 and word2 is bot h in the list.

Give a word array and two words, and return the shortest distance of the two words in the array. Assume that two words are different and are in the array.

Java:

public int shortestdistance (string[] words, String word1, String word2) {   int m=-1;   int n=-1;    int min = integer.max_value;    for (int i=0; i<words.length; i++) {        String s = words[i];        if (Word1.equals (s)) {            m = i;            if (n!=-1)                min = math.min (min, m-n);        } else if (word2.equals (s)) {            n = i;            if (m!=-1)                min = math.min (min, n-m);        }   }    return min;}

Python:

# Time:  O (N) # Space:o (1) class solution:    # @param {string[]} words    # @param {string} word1    # @param {Strin G} word2    # @return {integer}    def shortestdistance (self, words, word1, word2):        dist = float ("inf")        I, index1, Index2 = 0, none, none while        i < Len (words):            if words[i] = = Word1:                index1 = i            elif words[i] = = Word2:                index2 = i            if index1 is not none and Index2 are not none:                dist = min (dist, ABS (INDEX1-INDEX2)) 
   i + = 1        return dist

C++:

Class Solution {public:    int shortestdistance (vector<string>& words, String word1, String word2) {        int P1 =-1, p2 =-1, res = Int_max;        for (int i = 0; i < words.size (); ++i) {            if (words[i] = = word1) P1 = i;            else if (words[i] = = word2) P2 = i;            if (P1! =-1 && P2! =-1) res = min (res, ABS (P1-P2));        }        return res;    }};

C++:

Class Solution {public:    int shortestdistance (vector<string>& words, String word1, String word2) {        int idx =-1, res = Int_max;        for (int i = 0; i < words.size (); ++i) {            if (words[i] = = Word1 | | words[i] = = Word2) {                if (idx! =-1 &&am P WORDS[IDX]! = Words[i]) {                    res = min (res, I-IDX);                }                idx = i;            }        }        return res;    }};

Similar topics:

[Leetcode] 244. Shortest word Distance II shortest word Distance II

[Leetcode] 245. Shortest word Distance III shortest word Distance III

[Leetcode] 243. Shortest word Distance shortest word distance

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