Leetcode 53. Maximum Subarrayjava Language

Source: Internet
Author: User

Find the contiguous subarray within an array (containing at least one number) which have the largest sum. For example, given the array [ -2,1,-3,4,-1,2,1,-5,4],the contiguous subarray [4,-1,2,1] have the largest sum = 6.

Test instructions: To find the largest and most contiguous sub-arrays

Public class solution {    public int maxsubarray (int[] nums )  {        int len=nums.length;         if (nums==null | |  len==0) return 0;         int max=nums[0];          int curSum=nums[0];          for (int i=1;i<len;i++) {              if (cursum>0) {                  curSum+=nums[i];              }else{                  cursum=nums[i];          &nBsp;  }             max=math.max ( Cursum,max);         }          return max;            }}

PS: The first way of thinking, gradually accumulate cycle.

There is also a way of thinking that can be done with dynamic planning.

Public class solution {    public int maxsubarray (int[] nums )  {        int len=nums.length;         if (nums==null | |  len==0) Return 0;        //dp[i] represents the largest and at the end of Nums[i].         int[] dp=new int[len];         dp[0]=nums[0];        int MAX=dp[0];         for (int i=1;i<len;i++) {             if (dp[i-1]<0) {                 dp[i]=nums[i];             }else{                dp[i]=dp[i-1]+nums[i];             }            max=math.max (Dp[i],MAX);         }        return MAX;     }}

Leetcode 53. Maximum Subarrayjava Language

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