Leetcode 7. Reverse Integer (Python)

The problem is relatively simple, but there is something wrong with this question ....

There is no limit to the integer operation in Python, but the OJ system requires a large number of outputs of 0 (the title is not stated, but can be seen in test case)

So I stole a lazy,,,

Class solution (Object):    def reverse (self, X): "" "        : Type x:int        : Rtype:int        " ""    s= "    if x= =0:return 0    if x<0:s+= '-'    x=abs (x) while    x!=0:    s+=str (x%10)    X=X/10    i=int (s)    If i>2147483647 or i<-2147483647:        return 0    return I        

　　

Leetcode 7. Reverse Integer (Python)