[LeetCode] Compare Version Numbers

[LeetCode] Compare Version Numbers

Compare two version numbers version1 and version1.
If version1> version2 return 1, if version1 <version2 return-1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and.Character.
The.Character does not represent a decimal point and is used to separate number sequences.
For instance,2.5Is not "two and a half" or "half way to version three", it is the second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

Credits:
Special thanks to @ ts for adding this problem and creating all test cases.

public class Solution {    public int compareVersion(String version1, String version2) {        String[] v1 = version1.split("\\.");        String[] v2 = version2.split("\\.");        for(String s:v1){        System.out.println(s);        }        for(int i=0;i
 
  n2){        return 1;        }else if(n1
  
   0) return -1;        }        }else if(v1.length>v2.length){        for(int i=v2.length;i
   
    0) return 1;        }        }        return 0;    }}