Leetcode--compare Version Numbers

Compare numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return-1, otherwise ret Urn 0.

Assume that the version strings is non-empty and contain only digits and the.Character.
The.Character does not represent a decimal point and was used to separate number sequences.
For instance,2.5is not "both and a half" or "half-to-version three", it is the fifth Second-level revision of the second first-level re Vision.

Here are an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

Class Solution {public:    int compareversion (string version1, String version2) {        <span style= "White-space:pre "></span>vector<int> S1 = String_to_int (version1);vector<int> s2 = string_to_int (version2); int n = S1.size (); int m = S2.size (); int hold = N>m? m:n;for (int i=0; i


Leetcode--compare Version Numbers