The Employee
table holds all employees. Every employee has an ID, and there is also a column for the department ID.
+----+-------+--------+--------------+| Id | Name | Salary | DepartmentID |+----+-------+--------+--------------+| 1 | Joe | 70000 | 1 | | 2 | Henry | 80000 | 2 | | 3 | Sam | 60000 | 2 | | 4 | Max | 90000 | 1 | | 5 | Janet | 69000 | 1 | | 6 | Randy | 85000 | 1 |+----+-------+--------+--------------+
The Department
table holds all departments of the company.
+----+----------+| Id | Name |+----+----------+| 1 | IT | | 2 | Sales |+----+----------+
Write a SQL query to find employees who earn the top three salaries in each of the department. For the above tables, your SQL query should return the following rows.
+------------+----------+--------+| Department | Employee | Salary |+------------+----------+--------+| IT | Max | 90000 | | IT | Randy | 85000 | | IT | Joe | 70000 | | Sales | Henry | 80000 | | Sales | Sam | 60000 |+------------+----------+--------+
Select D1.name as department, E1.name as employee, E1.salary as salary from department D1, employee E1 where (
select count (distinct e2.salary) from Employee E2 where e2.salary > e1.salary and E2.departmentid = E1.depart Mentid) < 3 and d1.id = E1.departmentid;
Leetcode Department Top Three salaries