# Leetcode-maximum Gap

Source: Internet
Author: User

Maximum Gap

2015.1.23 15:00

Given an unsorted array, find the maximum difference between the successive elements in its sorted form.

Try to solve it in linear time/space.

Return 0 If the array contains less than 2 elements.

Assume all elements in the array is non-negative integers and fit in the 32-bit signed integer range.

Solution:

This are not a O (n) solution, but O (n * log (n)). Sort the array and find the maximal gap.

As for a linear solution, I ' m searching for it ...

Discussions Online said it could be solved using the bucket sort, but the doesn ' t really satisfy O (n) time scale, right? At least I wouldn ' t take it for O (n).

Accepted Code:

`1 //1AC, not a O (n) solution, though, one not yet come ...2#include <algorithm>3 using namespacestd;4 5 classSolution {6  Public:7     intMaximumgap (vector<int> &num) {8 sort (Num.begin (), Num.end ());9         intN;Ten          Onen = (int) num.size (); A         if(N <2) { -             return 0; -         } the          -         inti; -         intAns = ABS (num[0]-num[1]); -          for(i =2; I < n; ++i) { +ans = max (ans, ABS (Num[i-1] -num[i])); -         } +          A         returnans; at     } - Private: -     intMaxConst int&x,Const int&y) { -         returnx > y?x:y; -     } -      in     intAbsConst int&x) { -         returnX >=0? X:-x; to     } +};`

Leetcode-maximum Gap

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