Basic Calculator II Topics
Ideas
Same as this: Basic Calculator I
Code
classexpressiontransformation { Public:stringtrans_to_postfix_expression_to_s (string);//Convert the resulting expression to a suffix expression Long Long intCalculate_from_postfix_expression ();//Calculate values based on suffix expressionPrivate: vector<string>Ans_vector_post;//store suffix expression stringpost_string;//store suffix expression};inline intPriorCharOP) {//Calculate priority function if(OP = =' + '|| OP = ='-') {return 1; }Else if(OP = =' * '|| OP = ='/'|| OP = ='% ') {return 2; }Else{return 0; }}Long Long intString_to_int (stringIn) {//Convert the input string to the corresponding number function Chars[ -]; for(inti =0; I < -; i++) {S[i] =' + '; } for(inti =0; I < in.size (); i++) {S[i] = In[i]; }Long Long intAnssscanf(S,"%lld", &ans);returnAns;}stringDeleteblank (stringIn) {stringAnsintSize = In.size (); for(inti =0; i < size; i++) {if(In[i]! ="') Ans.push_back (In[i]); }returnAns;}stringexpressiontransformation::trans_to_postfix_expression_to_s (stringIn) { Stack<char>Op//Operation Fu YiAns_vector_post.clear ();//suffix expression to hold an array for(inti =0; I < in.size ();) {Charc = In[i];if(' 0 '<= C && C <=' 9 ') {//Is digital direct insertion stringNumintJ for(j = i; J < In.size () &&' 0 '<= In[j] && In[j] <=' 9 '; J + +) {Num.push_back (in[j]); } ans_vector_post.push_back (num); i = j; }Else{if(c = =' (') {//is open parenthesis inserted directlyOp.push (' ('); }Else{if(c = =' ) ') {//Is closing the parentheses to output the operators in the original stack until the opening brackets are encountered, note that the opening brackets are discarded while(Op.top ()! =' (') {stringTemp Temp.push_back (Op.top ()); Ans_vector_post.push_back (temp); Op.pop (); } op.pop (); }Else{//If it is subtraction to take surplus if(Op.empty ()) {//Operation Fu Yi is empty and is inserted directlyOp.push (c); }Else{if the scanned operator takes precedence over the top of the stack operator, the operator is pressed into the stack. Otherwise, the stack operator pops up to the end of the array ans until it encounters a lower priority than the scan-to operator or stack, and presses the scanned operator into the stack if(Prior (c) > Prior (Op.top ())) {Op.push (c); }Else{ while(!op.empty () && Prior (c) <= Prior (Op.top ())) {stringTemp Temp.push_back (Op.top ()); Ans_vector_post.push_back (temp); Op.pop (); } op.push (c); }}}} i++; } } while(!op.empty ()) {//Note the output of the remaining operator Ching Operation stringTemp Temp.push_back (Op.top ()); Ans_vector_post.push_back (temp); Op.pop (); } post_string.clear ();//Constructs a string and returns for(inti =0; I < ans_vector_post.size (); i++) {post_string + = Ans_vector_post[i]; }returnpost_string;}Long Long intExpressiontransformation::calculate_from_postfix_expression () {//using the stack on the suffix expression evaluation, directly from the suffix expression left to right scan, encountered the number in the stack, encountered the character on the top of the stack two numbers out, and then put into the stack Stack<long long int>Ans_post; for(inti =0; I < ans_vector_post.size (); i++) {Long Long intx, y;if(' 0 '<= ans_vector_post[i][0] && ans_vector_post[i][0] <=' 9 ') {Ans_post.push (String_to_int (ans_vector_post[i)); }Else{y = Ans_post.top ();//Note the order, here is like xy+ is X+yAns_post.pop (); x = Ans_post.top (); Ans_post.pop ();if(ans_vector_post[i][0] ==' + ') {Ans_post.push (x + y); }Else if(ans_vector_post[i][0] =='-') {Ans_post.push (x-y); }Else if(ans_vector_post[i][0] ==' * ') {Ans_post.push (x * y); }Else if(ans_vector_post[i][0] =='/') {Ans_post.push (x/y); }Else{ans_post.push (x% y); } } }returnAns_post.top ();}classSolution { Public:intCalculatestrings) {expressiontransformation E; s = Deleteblank (s); e.trans_to_postfix_expression_to_s (s);intPostans = E.calculate_from_postfix_expression ();returnPostans; }};
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Leetcode OJ Basic Calculator II