Linux && vim Batch Replacement

String substitution for Linux batch files

Sed-i "s/oldstring/newstring/g" ' grep oldstring-rl path '

Vim Multi-line substitution:
: 1,2s/str1/str2/g replaces only "str1" into "str2" in line 1th through 2nd in the file.

: s/vivian/sky/replaces the current line the first Vivian is sky
: S/vivian/sky/g replaces the current line all Vivian are sky

: N, $s/vivian/sky/replaces the first Vivian of each row in the nth row to the last row is sky
: N, $s/vivian/sky/g replace the nth line to the last row all Vivian are sky
N is a number, if n is. That represents the beginning of the current line to the last row

:%s/vivian/sky/(equivalent to: g/vivian/s//sky/) replaces the first Vivian of each line as Sky
:%s/vivian/sky/g (equivalent to: g/vivian/s//sky/g) replaces all Vivian in each row as Sky

You can use # as a delimiter, at which time the middle/not as a delimiter
: s#vivian/#sky/# Replace the current row the first vivian/is sky/
:%s+/oradata/apras/+/user01/apras1+ (use + to replace/):/oradata/apras/Replace with/user01/apras1/

Delete a ^m in text
Problem description: For line breaks, Windows uses a carriage return (0a0d) to indicate that Linux is a carriage return (0A). This way, when you copy a file on a window to UNIX, there is always a ^m. Write a shell or C program that uses a newline character (0D) that filters Windows files under UNIX.
· Using the command: Cat filename1 | tr-d "^v^m" > NewFile;
· Use command: sed-e "s/^v^m//" filename > OutputFileName. It is important to note that in 1, 22 methods, ^v and ^m refer to Ctrl + V and ctrl+m. You have to do the input manually, not paste it.
· In VI Processing: First use VI to open the file, and then press the ESC key, followed by the command:%s/^v^m//.
· :%s/^m$//g
If the above method is useless, the correct solution is:
· Tr-d "/R" < src >dest
· Tr-d "/015" dest
· Strings A>b

Other
Use the: s command to implement a string substitution. Specific uses include:
: s/str1/str2/replaces the first occurrence of a string in a line with a string str2 str1
: S/str1/str2/g replaces all occurrences of strings in a line with a string str2 str1
:., $ s/str1/str2/g Replace all occurrences of the current line to the end of the string with the string str2 str1
: 1,$ s/str1/str2/g replaces all occurrences of strings in the body with a string str2 str1
: g/str1/s//str2/g function Ibid.
You can see from the Replace command above that the G is placed at the end of the command to replace each occurrence of the search string, without g, which means that only the search
Replace the first occurrence of the string, and G at the beginning of the command to replace all rows in the body that contain the search string

Linux && vim batch replacement