Linux shell statement-based program

Shell code #! /Bin/bash for a in $ @ do case $ a in file = *) file = "$ (echo $ a | sed's /. * = //; s/% sp % // G') "; list) mode = list; find = *) mode = find var = "$ (echo $ a | sed's /. * = //; s/, // G') "; add = *) mode = add var =" $ (echo $ a | sed's /. * = // ') "; del = *) mode = del var =" $ (echo $ a | sed's /. * = //; s/, // G') "; help) cat <EOF Word Table program usage: voct file = [list | help | add = | del = | find =] file = All spaces in the file name should be replaced by % sp %, the file name cannot contain % sp % list to list all projects in the file. help shows this help add = add entry 1 [, add entry 2, add entry 3...] del = Delete entry 1 [, delete entry 2, delete entry 3...] find = search for Entry 1 [, search for entry 2, search for entry 3...] an entry and an entry are separated by commas (,) to start with a row. For example, del = abc can delete an entry. If you want to delete an entry from abc and abcd, use find to find the entry first, then, use the independent start of the entry to be deleted (not overlapped with other entries) to delete the equal sign and no equal sign can be added. We recommend that you use "--" instead of EOF exit esac case $ mode in list) cat "$ file"; find) for var3 in $ var do cat "$ file" | grep -- color = never $ var3 done; del) for var0 in $ var do sed-I "/^ $ var0/d" "$ file" done; add) touch $ file have = 1 [$ have = 1] & var2 = "$ (echo $ var | sed's/% sp % // g; s /,, /# enter #/G ') "& echo $ var2>" $ file "& sed-I's/# enter #/\ n/G'" $ file "esac done