Loss accuracy of floating-point data-to-integer type (c + +)

The following code: HTTP://IDEONE.COM/XCGHGW

#include <iostream>using namespacestd;intMain () {//your code goes here    inti =0; I=9.0*0.6+0.6; cout<< I <<Endl; I=9.0*0.6+0.6; cout<< I <<Endl; I= (Double)(9.0*0.6+0.6); cout<< I <<Endl; cout<< (Double)(9.0*0.6+0.6); return 0;}

The intention is to print 4 x 6;

But the printing results are:

5

5

5

6;

Reason is

9.0 * 0.6 of the return value is likely to be 5.3999...,+ 0.6 after 5.9999 ... Cast to int type is 5;

Solutions are:

Do not assign a double type of data to an integral type, or it may appear to be inconsistent with your original intention.

Loss accuracy of floating-point data-to-integer type (c + +)