Lost's revenge hdu3341

AC automation + state compression DP, because the time limit card is relatively dead, the selection of the advanced and low levels may lead to TLE (O (∩ □╰) O). For details, see the notes.

# Include <iostream> # include <cstdio> # include <cstdlib> # include <cmath> # include <queue> # include <algorithm> # include <vector> # include <cstring> # include <stack> # include <cctype> # include <utility> # include <map> # include <string> # include <climits> # include <set> # include <string> # include <sstream> # include <utility> # include <ctime> Using STD:: priority_queue; Using STD: vector; Using STD: swap; Using STD: S Tack; Using STD: sort; Using STD: Max; Using STD: min; Using STD: pair; Using STD: Map; Using STD: string; using STD: CIN; Using STD: cout; Using STD: Set; Using STD: queue; Using STD: string; Using STD: istringstream; Using STD :: make_pair; Using STD: Getline; Using STD: greater; Using STD: Endl; Using STD: multimap; typedef long ll; typedef unsigned long ull; typedef pair <int, int> pair; typedef multimap <in T, int> MMAP; const int maxn (510); const int sigma_size (4); const int maxm (110); const int MaxE (4000010 ); const int maxh (18); const int INFI (INT_MAX-1)> 2); const int Mod (20090717); const ull Lim (limit 000ull); int MP [128]; struct AC {int ch [maxn] [sigma_size]; int Val [maxn], F [maxn]; int size; void Init () {memset (CH [0], 0, sizeof (CH [0]); F [0] = Val [0] = 0; size = 1;} inline int idx (char temp ){ Return MP [temp];} void insert (char * s) {int u = 0, ID; For (; * s; ++ S) {id = idx (* s); If (! Ch [u] [ID]) {memset (CH [size], 0, sizeof (CH [size]); Val [size] = 0; ch [u] [ID] = size ++;} u = CH [u] [ID];} Val [u] + = 1;} int que [maxn]; int front, back; void construct () {front = back = 0; int cur, U; For (INT I = 0; I <sigma_size; ++ I) {u = CH [0] [I]; If (u) {que [back ++] = u; F [u] = 0 ;}} while (front <back) {cur = que [Front ++]; for (INT I = 0; I <sigma_size; ++ I) {u = CH [cur] [I]; If (u) {que [Back ++] = u; F [u] = CH [f [cur] [I]; Val [u] + = Val [f [u];} else ch [cur] [I] = CH [f [cur] [I] ;}}}; ac; int base [4]; int quant [4]; inline int encode () {return quant [0] * base [0] + quant [1] * base [1] + quant [2] * base [2] + quant [3] * base [3 ];} bool vis [maxn] [15010]; int table [maxn] [15010]; int code; // note that each State encoding can be obtained by subtraction recursion, do not recalculate int DFS (int u) {If (vis [u] [Code]) return table [u] [Code]; int & cur = table [u] [Code]; cur = 0; Int ts, temp; For (INT I = 0; I <sigma_size; ++ I) if (quant [I]) {-- quant [I]; code-= base [I]; TS = ac. ch [u] [I]; temp = DFS (TS) + AC. val [ts]; cur = temp> cur? Temp: cur; code + = base [I]; ++ quant [I];} vis [u] [Code] = true; return cur;} void solve () {memset (VIS, 0, sizeof (vis [0]) * AC. size); Code = encode (); DFS (0); printf ("% d \ n", table [0] [Code]);} Char STR [60]; int main () {MP ['a'] = 0; MP ['C'] = 1; MP ['G'] = 2; MP ['T'] = 3; int N, n_case (0); While (scanf ("% d", & N), n) {AC. init (); For (INT I = 0; I <n; ++ I) {scanf ("% s", STR); AC. insert (STR);} AC. construct (); scanf ("% s", STR); quant [0] = quant [1] = quant [2] = quant [3] = 0; for (char * Pi = STR; * PI; ++ PI) ++ quant [MP [* Pi]; base [3] = 1; // If 'A' is used as the low position, it will be TLE. Note that the status of each bit is quant + 1 base [2] = quant [3] + 1; base [1] = (quant [2] + 1) * base [2]; base [0] = (quant [1] + 1) * base [1]; printf ("case % d:", ++ n_case); solve ();} return 0 ;}