Mark PHP Security Issues

Input string where all PHP considers int is cast, such as

$a'asdfgh'；//字符串类型的a
echo$a[2]；  //根据php的offset 会输出'd'
echo$a[x]；  //根据php的预测，这里应该是int型，那么输入string，就会被intval成为0 也就是输出'a'

If switch is the case of a numeric type, switch converts the arguments in it to the int type. As follows:

$i ="2abc";switch ($i) {case0:case1:case2:    echo"i is less than 3 but not negative";    break;case3:    echo"i is 3";}

Loosely-compared tables

'). addclass (' pre-numbering '). Hide (); $ (this). addclass (' has-numbering '). Parent (). append ($numbering); for (i = 1; i <= lines; i++) {$numbering. Append ($ ('

'). Text (i)); }; $numbering. FadeIn (1700); }); });

The above describes the mark PHP security issues, including aspects of the content, I hope that the PHP tutorial interested in a friend helpful.

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