# [Matlab] Algorithm Craftsman video 1: Digital signal processing simulation and realization the first signal source generation and filtering 1, 2

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https://www.bilibili.com/video/av17343551

https://www.bilibili.com/video/av17707835

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https://www.bilibili.com/video/av16683579

Course-Related code:

`The generation and filtering of the 1% firdesign.m% author: the author of the copy is the UP master.  % June 3, 2018 18:12:35clear; Close all;clc;fc1 = 10;FC2 = 100;FC3 = 450;      % of three frequency components FS = 1000; % Sample Frequency point_s = 1000;   % Sample point time = [1:point_s]/fs;    % time domain sampling temporal variable delta_f = 1*fs/point_s; % Frequency Resolution SIN_S1 = 0.5*sin (2*pi*fc1*time); sin_s2 = 1.1*sin (2*pi*fc2*time); sin_s3 = 0.8*sin (2*pi*fc3*time); sin_s = Sin_s1 + Sin_s2 + sin_s3; % generation and synthesis signal fft_s1 = FFT (sin_s), figure (1), subplot (2,1,1);p lot (time,sin_s), title (' Original Time domain signal '); f = 0:point_s/2-1;f = F*delta_ F;danbianfudu = 2*abs (FFT_S1 (1:POINT_S/2)), subplot (2,1,2);p lot (F,danbianfudu), title (' Frequency domain amplitude characteristics '),%%%%%% filter processing% Design low-pass filter , the upper cutoff frequency is FC = 120hz% WC = fc/(FS/2);    N = 128; % Filter Order FC = 120;WC = fc/(FS/2); Fir1_lowpass_filter = Fir1 (N,WC); figure (2); Freqz (Fir1_lowpass_filter); % view amplitude characteristics and phase characteristics (normalized frequency) title (' 128 Order lowpass filter '),% implementation filter FILTER_SIN_S1 = filter (fir1_lowpass_filter,1,sin_s); fft_low_filter = FFT (FILTER_SIN_S1); Figure (3), subplot (2,1,1);p lot (time,filter_sin_s1), title (' Low Pass filtered time domain waveform ') subplot (2,1,2);d Anbianfudu = 2*abs (fft_low_ FIlter (1:POINT_S/2));p lot (F,danbianfudu), title (' Frequency amplitude characteristics after low pass filtering '),% filter processing% Design a high-tube filter, cutoff frequency is 15HZFC =; WC = fc/(FS/2); % Video Courseware write 0.15, because this example wc=0.15 corresponds to 75Hz can also filter out 75Hz, I take 20hzfir1_hp_filter = Fir1 (N,WC, ' High '); figure (4); FREQZ (fir1_hp _filter); filter_sin_s2 = filter (fir1_hp_filter,1,sin_s); fft_high_filter = FFT (FILTER_SIN_S2); figure (5); subplot ( 2,1,1);p lot (time,filter_sin_s2), title (' High Pass filtered time domain waveform '), subplot (2,1,2);d Anbianfudu = 2*abs (Fft_high_filter (1:point_s  /2));p lot (F,danbianfudu), title (' High-pass filtered frequency domain amplitude characteristics ');`

Study questions: How do I implement a band-pass filter and a band-stop filter?

`% bandpass filter% only let 100Hz through%WC1 = 50/(FS/2);%wc2 = 400/(FS/2); fc1 = 50;FC2 = 400;WC1 = FC1/(FS/2); WC2 = FC2/(FS/2); fir1_ba  Nd_pass_filter = Fir1 (n,[wc1 WC2], ' bandpass '); %ftype%figure (6); Freqz (fir1_band_pass_filter);% Implementation filter FIR1_BP_S1 = filter (fir1_band_pass_filter,1,sin_s); fft_bp_ Filter = FFT (FIR1_BP_S1), figure (7), subplot (2,1,1);p lot (time, fir1_bp_s1), title (' Band-pass filter post-filter waveform '); subplot (2,1,2); Danbianfudu = 2*abs (Fft_bp_filter (1:POINT_S/2));p lot (F,danbianfudu), title (' Band-pass filtered frequency amplitude characteristics '),% Band-stop filter% only 100Hz passed%WC1 = 50/(FS/2);%wc2 = 400/(FS/2); fc1 = 50;FC2 = 400;WC1 = FC1/(FS/2); WC2 = FC2/(FS/2); fir1_band_stop_filter = Fir1 (  N,[WC1 WC2], ' stop '); %ftype%figure (8); Freqz (fir1_band_stop_filter);% Implementation filter FIR1_BS_S1 = filter (fir1_band_stop_filter,1,sin_s); fft_bs_ Filter = FFT (FIR1_BS_S1), figure (9), subplot (2,1,1);p lot (time, fir1_bs_s1), title (' Band filter After filter waveform '); subplot (2,1,2); Danbianfudu = 2*abs (Fft_bs_filter (1:POINT_S/2));p lot (F,danbianfudu), title (' frequency amplitude characteristics after band-stop Filtering ');`

[Matlab] algorithm Craftsman video 1: Digital signal processing simulation and implementation the first signal source generation and filtering 1, 2

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