My homework.

Question No. 1 .

(1)

A(Save as afun1.m)

function f = Afun1 (x);

f= (x^2-1) * (x<=-5) + (X*cos (x)) * (x>-5&x<5) + (x+5) * (x>=5);

B [Email protected] (x) (x^2-1) * (x<=-5) + (X*cos (x)) * (x>-5&x<5) + (x+5) * (x>=5);

C [Email protected] (x) (x.^2-1). * (x<=-5) + (X.*cos (x)). * (x>-5&x<5) + (x+5). * (x>=5);

(2)

A

Clc,clear

A=1;

X=[-15:0.1:15];

While a<=301

Z (a) =afun1 (x (a));

a=a+1;

End

Z

B

Clc,clear

[Email protected] (x) (x^2-1) * (x<=-5) + (X*cos (x)) * (x>-5&x<5) + (x+5) * (x>=5);

A=1;

X=[-15:0.1:15];

While a<=301

Z (a) =y (x (a));

a=a+1;

End

Z

C x=[-15:0.1:15]; Z=y (x);

(3)

A:fplot (' Afun1 ', [ -15,15]);

B,C: fplot (y,[-15,15]);

(4)

On the basis of the second question code

A,B:plot (x,z);

C: plot (x,z);

question No. 2

Rand (' state ', sum (clock));

A=rand (3,5);

B=rand (4,7);

C=rand (6,9);

Ma=max (Max (a));

[Ax,ay]=find (A==max (Max (a)));

Mb=max (max (b));

[Bx,by]=find (B==max (max (b)));

Mc=max (Max (c));

[Cx,cy]=find (C==max (Max (c)));

question No. 3

[Email protected] (x) sin (x). *x;

Fplot (y,[0,100]);

% has a minimum point

% Estimated position

Clc,clear

[Email protected] (x) sin (x). *x;

X0=[5,10,18,22,30,37,41,49,55,61,68,74,80,87,92,99];

[X1,yval]=fminunc (' Y ', 5);

Question Fourth

Give the Model:

(symbol description)

Model

Give the code:

Clc,clear

c=[1,0,0,0,1,0,1,0;

1,1,0,0,1,0,0,1;

1,0,1,0,1,0,0,0;

0,1,0,1,0,0,0,1;

0,0,1,0,0,1,0,0;

0,0,0,1,0,1,0,1;

];

C=-c;

C=c ';

%c ' is a

B=ones (8,1);

B=-b;

F=ones (6,1);

Ub=ones (6,1);

Lb=zeros (6,1);

Intcon=1:6;

[X,val]=intlinprog (F,intcon,c,b,[],[],lb,ub);

Result of Operation:

X =[1,0,0,1,1,0] '

val = 3;

"Problem Transformation"

The number of the students to 34,29,42,21,56,18,71 The point marking for 1~7,

Set 1~2,3; 2~3,4,5; 4~5,6,7; 5~6;6~7 's Edge marking is 1~11

Then The weight of the first edge is 63,76,71,50,85,63,77,39,92,74,89

You can prove that you should not take a heavy vertex.

The problem is converted to two on this side of the line , in the case of not taking the heavy vertex, the maximum weight of the two edges

"Symbol description"

the weight of the side of the section I is represented by fi

Xi represents whether Iis selected (is 1, no 0)

"Build Model"

Max Fi*xi

s.t

"Code as follows"

Clc,clear

f=[-63;-76;-71;-60;-85;-63;-77;-39;-98;-74;-89];intcon=11;

A=[1 1 0 0 0 0 0 0 0 0 0;

1 0 1 1 1 0 0 0 0 0 0;

0 1 1 0 0 1 0 0 0 0 0;

0 0 0 1 1 1 1 1 1 0 0;

0 0 0 0 1 0 1 0 0 1 0;

0 0 0 0 0 0 0 1 0 1 1;

0 0 0 0 0 0 0 0 1 0 1];

B=ones (7,1);

Aeq=ones (1,11); beq=2;

Lb=zeros (11,1); Ub=ones (11,1);

[X,fval]=intlinprog (F,intcon,a,b,aeq,beq,lb,ub)

Val=-fval

"The results are as follows"

Lp:optimal objective value is-174.000000.

X =[0 1 0 0 0 0 0 0 1 0 0] '

FVal =-174

Val =174

My homework.