Nyoj 949 Harry Potter (detail)

Harry Potter time limit: 1000 MS | memory limit: 65535 kb difficulty: 3

Description

Harry learned three new ways of magic. He could use the first magic to turn a gram of sand into B grams of metal. He could use the second magic to turn C grams of metal into D grams of gold, you can use the third magic to turn e-grams of gold into F-grams of sand. Harry's two friends Ron and Hermione are very happy to know, but Ron and Hermione have a disagreement, Ron thinks Harry can use these three magic to get infinite gold, hermione felt that there could be no limit. Harry wants to know who is right.

Input

Input 6 integers A, B, C, D, E, F
(0 <= A, B, C, D, E, F <= 1000)

Output

The output is correct. If Ron is the correct output, "Ron" is output; otherwise, "Hermione" is output"

Sample Input

100 200 250 150 200 50 250100 200 200 1001 1 0 1 1100 1 100 1 0 1

Sample output

Ronhermioneronron

Uploaded

ACM _ Wang Ying

Idea: forward to gold, "reverse gold (Ron)

Forward: K = B/c * d

Reverse: q = (k/E) * F

W = (Q/a) * B

P = (W/C) * D // reverse gold

Note that the input value can be 0.

1. When a = 0 BCD, infinite gold ron C = 0 & D infinitely turns out gold Ron

2. When (a = 0 | C = 0 | E = 0) & B, D, and F are infinite gold

3. when (A = 0 & B = 0) | (E = 0 & F = 0) | (C = 0 & D = 0) there is a link in herminoe that cannot be converted

(The syy code is simpler than the one I wrote)

 #include<stdio.h>int main(){    double a,b,c,d,e,f;    while(~scanf("%lf%lf%lf%lf%lf%lf",&a,&b,&c,&d,&e,&f))    {        if(c==0&&d)        {            printf("Ron\n");            continue;        }        if(a==0&&b&&c&&d)        {            printf("Ron\n");            continue;        }        if((a==0||c==0||e==0)&&b&&d&&f)        {            printf("Ron\n");            continue;        }        if((a==0&&b==0)||(e==0&&f==0)||(c==0&&d==0))        {            printf("Hermione\n");            continue;        }        double k=(b/c)*d;        double q=(k/e)*f;        double w=(q/a)*b;        double p=(w/c)*d;        if(p>k)            printf("Ron\n");        else            printf("Hermione\n");    }    return 0;}  

Nyoj 949 Harry Potter (detail)