Obtain the rang of repeated characters in the string in ios development

Obtain the rang of repeated characters in the string in ios development

In iOS development, you will often encounter the problem of processing strings. For a string, you will often encounter repeated characters that must be processed, the following code processes repeated characters:

 

/*** Return the location of the repeated characters ** @ param text the initialized string * @ param findText the character to be searched ** @ return returns the location of the repeated characters */-(NSMutableArray *) getRangeStr :( NSString *) text findText :( NSString *) findText {NSMutableArray * arrayRanges = [NSMutableArray limit: 20]; if (findText = nil & [findText isw.tostring: @ ""]) {return nil;} nsange rang = [text rangeOfString: findText]; if (rang. location! = NSNotFound & rang. length! = 0) {[arrayRanges addObject: [NSNumber numberWithInteger: rang. location]; nsange rang1 = {0, 0}; NSInteger location = 0; NSInteger length = 0; for (int I = 0; I ++) {if (0 = I) {location = rang. location + rang. length; length = text. length-rang. location-rang. length; rang1 = NSMakeRange (location, length);} else {location = rang1.location + rang1.length; length = text. length-rang1.location-rang1.length; rang1 = NSMakeRange (location, length);} rang1 = [text rangeOfString: findText options: NSCaseInsensitiveSearch range: rang1]; if (rang1.location = NSNotFound & rang1.length = 0) {break;} else [arrayRanges addObject: [NSNumber numberWithInteger: rang1.location];} return arrayRanges;} return nil ;}

The returned array object is the location of repeated characters in text. It is conveniently used to obtain rang = {array [I], findText. length}