[Original] arrange all the 0 elements in an array to the right of the array, and the relative sequence of other elements remains unchanged.

Source: Internet
Author: User
Idea: First Initialize an array (newArr) of the same size as the given array (arr), and then place the elements not 0 in arr in newArr in sequence. In this case, we can consider that if we put * in the array to the left or right of the array, we only need to initialize all arrays *, then place the elements not * In arr on the left or right of newArr at a time.
Namespace test {class Program {static void Main (string [] args) {int [] arr = {, 5 }; int [] newArr = new int [arr. length]; int count = 0; for (int I = 0; I <arr. length; I ++) {if (arr [I]! = 0) {newArr [count] = arr [I]; count = count + 1 ;}} foreach (int m in newArr) {Console. write (m + "");} Console. readLine ();}}}

 

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