P1538 digital dance and p1538 Spring Dance

P1538 digital dance and p1538 Spring Dance
Background

Students of HNSDFZ are preparing to rehearse a dance to celebrate the Spring Festival.

Description

In the era of more and more cooperation, what people pay attention to is not the dance of individual figures, but the collective arrangement.

In order to cope with the annual countdown, the students decided to "Digital Dance ". As the name implies, everyone is lined up with several numbers-___-| what's more innovative is that everyone is on the ground to ensure that they are in the vertical and horizontal directions.

Now let's show you the numbers and their requirements. Please program them to simulate the beautiful posture of the students.

Input/Output Format

Input Format:

 

The first behavior k. K indicates the size of a number.

The second act is a string composed of numbers, that is, the numbers to be displayed.

 

Output Format:

 

Output as required by the question.

 

Input and Output sample input sample #1:

21234567890

Output sample #1:

      --   --        --   --   --   --   --   --    |    |    | |  | |    |       | |  | |  | |  |   |    |    | |  | |    |       | |  | |  | |  |      --   --   --   --   --        --   --         | |       |    |    | |  |    | |  |    | |  |   | |       |    |    | |  |    | |  |    | |  |      --   --        --   --        --   --   -- 

Description

Each number has one space before it, and all numbers are aligned.

K <= 30, the length of s cannot exceed 255

We recommend that you do not save the output directly.

If you have any questions about the size and k, please understand.

 

Find the rule...

Simulation... ,

  1 #include<iostream>  2 #include<cstdio>  3 #include<cstring>  4 #include<cmath>  5 using namespace std;  6 char a[438];  7 void read(int & n)  8 {  9     char c='+';int x=0; 10     while(c<'0'||c>'9') 11     c=getchar(); 12     while(c>='0'&&c<='9') 13     { 14         x=x*10+(c-48); 15         c=getchar(); 16     } 17     n=x; 18 } 19 void kong() 20 {printf(" ");} 21 void heng() 22 {printf("-");} 23 void shu() 24 {printf("|");} 25 int main() 26 { 27     int n; 28     read(n); 29     scanf("%s",a); 30     int la=strlen(a); 31     for(int i=0;i<strlen(a);i++) 32     { 33         kong(); 34         if(a[i]=='1'||a[i]=='4') 35         { 36             for(int k=1;k<=n;k++) 37             kong(); 38         } 39         else 40         { 41             for(int k=1;k<=n;k++) 42             heng(); 43         } 44         kong(); 45         kong(); 46     } 47     printf("\n"); 48     for(int l=1;l<=n;l++) 49     { 50         for(int i=0;i<la;i++) 51         { 52             if(a[i]=='1'||a[i]=='2'||a[i]=='3'||a[i]=='7') 53             { 54                 for(int k=1;k<=n+1;k++) 55                 kong(); 56                 shu(); 57             } 58                  59             else if(a[i]=='5'||a[i]=='6') 60             { 61                 shu(); 62                 for(int k=1;k<=n+1;k++) 63                 kong(); 64             } 65             else 66             { 67                 shu(); 68                 for(int k=1;k<=n;k++) 69                 kong(); 70                 shu(); 71             } 72             kong(); 73         } 74         printf("\n"); 75     } 76     for(int i=0;i<strlen(a);i++) 77     { 78         kong(); 79         if(a[i]=='1'||a[i]=='7'||a[i]=='0') 80         { 81             for(int k=1;k<=n;k++) 82             kong(); 83         } 84         else 85         { 86             for(int k=1;k<=n;k++) 87             heng(); 88         } 89         kong(); 90         kong(); 91     } 92     printf("\n"); 93     for(int l=1;l<=n;l++) 94     { 95         for(int i=0;i<la;i++) 96         { 97             if(a[i]=='1'||a[i]=='3'||a[i]=='4'||a[i]=='5'||a[i]=='7'||a[i]=='9') 98             { 99                 for(int k=1;k<=n+1;k++)100                 kong();101                 shu();102             }103                 104             else if(a[i]=='6'||a[i]=='8'||a[i]=='0')105             {106                 107                 shu();108                 for(int k=1;k<=n;k++)109                 kong();110                 shu();111             }112             else113             {114                 shu();115                 for(int k=1;k<=n+1;k++)116                 kong();117             }118             kong();119         }120         printf("\n");121     }122     for(int i=0;i<strlen(a);i++)123     {124         kong();125         if(a[i]=='1'||a[i]=='7'||a[i]=='4')126         {127             for(int k=1;k<=n;k++)128             kong();129         }130         else131         {132             for(int k=1;k<=n;k++)133             heng();134         }135         kong();136         kong();137     }138     return 0;139 }