Pass the array in the shell script to awk

If you encounter this problem, write it in your own way. Here, only the relevant part is shown.

# Getting the length of an array

Array_len = "'wc-l temp2 | awk '{print $1 }''"

Temp_index = 0

Declare-A array_date

# Assign values to arrays in Shell

For I in $ (cat temp2); do

Array_date [temp_index ++] = $ I

Done

 

# For (IX = 0; ix <$ array_len; ix ++); do

# Echo $ {array_date [ix]}

# Done

# Pass all contents in the shell array to awk

Awk-V string = "$ {array_date [*]}" 'In in {

# Split the string so that it is restored to the same content as the shell Array

Len = Split (string, date)

# You can do what you want later.

.....

 

Summary: All values in the array in the script are taken as one variable value and paid to the awk variable. The split is used to restore the data.