PAT1022. D-in A+b (20)

Source: Internet
Author: User

Enter two non-negative 10 binary integers A and B (<=230-1) and Output a+b D (1 < D <= 10) of the binary number.

Input format:

The input gives 3 integers a, B, and D, in turn, in one row.

Output format:

The D binary number of the output a+b.

Input Sample:

123 456 8

Sample output:


Note: D-binary, use the stack should be aware of the namespace.
1#include <stdio.h>2#include <stack>3 using namespacestd;4 /*5 Char str1[35];6 Char str2[35];7 void Reverse (char str1 [])8 {9 Char str[35];Ten for (int i=0;i<strlen (STR1); i++) One     { A Str[i] =str1[i];  -     } - for (int i=0;i<strlen (STR1); i++) the     { - Str1[strlen (STR1) -1-i]=str[i]; -     } - }*/ + intMainintargcChar**argv) - { +     inta,b,d; Astack<int>S; at     //reverse the two numbers -scanf"%d%d%d",&a,&b,&D); -     intsum=a+B; -      while(sum>=D) -     { -         intreminder=sum%D; insum=sum/D; - S.push (reminder); to     } + s.push (sum); -      while(!s.empty ()) the     { *printf"%d", ()); $ S.pop ();Panax Notoginseng     } -      the     return 0; +}
View Code

PAT1022. D-in A+b (20)

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