Phalanx (Hdu 2859)

Source: Internet
Author: User   Time limit:10000/5000 MS (java/others) Memory limit:32768/32768 K (java/others)
Total submission (s): 996 Accepted Submission (s): 468

problem DescriptionToday is Army day, but the servicemen was busy with the Phalanx for the celebration of the 60th anniversary of the PRC .
a phalanx is a matrix of size n*n with each element being a character (a~z or a~z), standing for the military branch of the S Ervicemen on that position.
For some special requirement it had to find out the size of the the max symmetrical sub-array. And with no doubt, the Central Military Committee gave this task to Alpcs.
a symmetrical matrix is such a matrix that it's symmetrical by the ' Left-down to right-up ' line. The element on the corresponding place should is the same. For example, this is a 3*3 symmetrical matrix:
InputThere is several test cases in the input file. Each case is starts with a integer n (0<n<=1000), followed by n lines which have n character. There won ' t is any blank spaces between characters or the end of line. The input file is ended with a 0. 
OutputEach test case is output one line, the size of the maximum symmetrical Sub-matrix. 
Sample Input3abxcybzca4zabacbababbccacq0 
Sample Output - 
Sourcemulti-university Training Contest 5-host by Nudt

#include <cstdio>#include<cstring>#include<iostream>#include<cmath>#include<vector>#include<algorithm>#include<string>using namespacestd;#defineN 1100#defineMOD 1000000007#defineMet (A, b) memset (A, B, sizeof (a))#defineINF 0x3f3f3f3fCharG[n][n];intDp[n][n];intMain () {intN;  while(SCANF ("%d", &N), N) {intI, J, I1, J1, max=1; Met (G,0); Met (DP,0);  for(i=0; i<n; i++) scanf ("%s", G[i]);  for(i=0; i<n; i++)         for(j=0; j<n; J + +)        {            if(i==0|| j==n-1) {Dp[i][j]=1; Continue; } i1=i, j1=J;  while(J1<n && i1>=0&& g[i1][j]==g[i][j1]) I1--, j1++; if((I-I1) >=dp[i-1][j+1]+1) Dp[i][j] = dp[i-1][j+1] +1; ElseDP[I][J] = iI1; Max=Max (max, dp[i][j]); } printf ("%d\n", Max); }    return 0;}

Phalanx (Hdu 2859)

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