PHP and MySQL for some simple operation

Source: Internet
Author: User
Tags php and php and mysql create database

Post Code First

The code is as follows:
<title> Database Related </title>
$con = mysql_connect ("localhost", "root", "root"); Link Database
if (! $con) {
Die (' Connection failed! ' . Mysql_error ()); To judge whether or not to succeed
/* IF (mysql_query ("CREATE DATABASE testdb", $con)) {//mysql_query query or Send command
echo "Create TestDB success";
echo "Reason for failure:". Mysql_error (); To determine whether a success was created
mysql_select_db ("TestDB", $con); Select the database that the link just created
$sql = "CREATE TABLE Persons
(PersonID int not NULL auto_increment,
FirstName varchar (15),
LastName varchar (15),
Age int)
"; Mysql Statement Creation Table
mysql_query ($sql, $con); Execute SQL statement

Mysql_close ($con); Close MySQL Connection

The key element is

1, linked to the database

2. Create a table

3, according to the needs of the table content to enrich

The above is the entire content of this article, I hope that the small partners can enjoy.

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