PHP array format output problem, ask the great God

I have one of the following tables


Excuse me, how can I get him to output the following array format according to type and typeid? Thank you

Array (  [0] = Array (            [0]=>            [1]=> Wedding service            [2]=> Machinery Equipment            [3]=> Hospital Medical            [4]=> Lighting            [5]=> Education and training            [6]=> Chemical paint            [7]=> Beauty fitness            [8]=> food            [9]=> Car service            ) [1] = = Array (            [0]=>            [1]= > General            [2]=> two columns            [3]=> three columns            [4]=> grid            ))

Reply to discussion (solution)

Read after query

while ($row = Mysql_fetch_assoc ($rs)) {  $res [$row [' type '] [] = $row [' Typevalue '];} $res = Array_values ($row);

Read after query

while ($row = Mysql_fetch_assoc ($rs)) {  $res [$row [' type '] [] = $row [' Typevalue '];} $res = Array_values ($row);

Xuzuning Moderator, I tried the next page error OH. $res [$row [' type '] [] parentheses here, removing or making an error.

Ruled out the discovery is this error, $res = Array_values ($row); What is the reason for this?

Oh, it's a missing bracket.
$res [$row [' type '] [] = $row [' Typevalue '];

Oh, it's a missing bracket.
$res [$row [' type '] [] = $row [' Typevalue '];

Xuzuning Moderator, change to your latest this, or will page error. Hint is this sentence, error, do not know what is the reason $res = Array_values ($row);

Hint error is warning:array_values () expects parameter 1 to is array, boolean given in

This line is pointed to $res = Array_values ($row);

It's my fault!
$res = Array_values ($res);

Oh, it's a missing bracket.
$res [$row [' type '] [] = $row [' Typevalue '];

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Fix the xuzuning moderator, is $res = Array_values ($row); Here is the wrong, $row out of the array is not an error, has been changed, thank you for your ideas.

It's my fault!
$res = Array_values ($res);

It's done. (*^__^*) hehe ... Thank you

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