PHP calculates age by ID number

Source: Internet
Author: User
Tags diff

function Getagebyid ($id) {

After this year's birthday is more than 1 years old
if (empty ($id)) return ";
$date =strtotime (substr ($id, 6,8));
Time stamp for Birth date
$today =strtotime (' Today ');
Get today's time stamp
$diff =floor (($today-$date)/86400/365);
To get a two-day difference in the approximate number of years

Strtotime plus the time stamp of the year after that date, compared to today's timestamp.
$age =strtotime (substr ($id, 6,8). ' + '. $diff. ' Years ') > $today? ($diff + 1): $diff;

return $age;

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