Php expects parameter 1 to be resource, array given error

If you are using encapsulated classes
For example
Function fetch_array ($ query, $ result_type = MYSQL_ASSOC ){
Return mysql_fetch_array ($ query, $ result_type );
}
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This error will be reported
This is because the $ query you passed is a Boolean value, while the parameter in mysql_fetch_array needs the resource type. This is because your program will determine that the parameter you passed is incorrect,
We can Copy codeThe Code is as follows: function fetch_array ($ query, $ result_type = MYSQL_ASSOC ){
Return @ mysql_fetch_array ($ query, $ result_type );
}

Use @ to Disable Error prompts, or
Use an interpretation statement to execute this statement,Copy codeThe Code is as follows: if (this parameter)
{
Run
}