PHP implementation method to calculate Easter date accurately

This article mainly introduces the method of PHP accurate calculation of Easter date, involving PHP operation date skills, very practical value, the need for friends can refer to the next

This example describes how PHP accurately calculates the Easter date. Share to everyone for your reference. Specific as follows:

<? Phpfunction Isleapyear ($nYEAR) {if (($nYEAR% 4 = = 0) and! ( $nYEAR% = = 0)) and ($nYEAR%. = 0)) {return TRUE;} else {return FALSE;}} function P ($a, $b) {return ($a-($a% $b))/$b; function Eastersunday ($nYEAR) {//The function is able to calculate the date//of eastersunday the 325,/ /But Mktime () starts at 1970-01-01!  if ($nYEAR < 1970) {$dtEasterSunday = Mktime (1,1,1,1,1,1970);} else {$nGZ = ($nYEAR% 19) + 1;  $nJHD = P ($nYEAR, 100) + 1;  $nKSJ = P (3 * $nJHD, 4)-12;  $nKORR = P (8 * $nJHD + 5, 25)-5;  $nSO = P (5 * $nYEAR, 4)-$nKSJ-10;  $nEPAKTE = ((one * $nGZ + + $nKORR-$nKSJ)% 30);  if ($nEPAKTE = = OR $nGZ = =) and $nEPAKTE = =) {$nEPAKTE = $nEPAKTE + 1;  } $nN = 44-$nEPAKTE;  if ($nN <) {$nN = $nN + 30;  } $nN = $nN + 7-(($nSO + $nN)% 7);  $nN = $nN + isleapyear ($nYEAR);  $nN = $nN + 59;  $nA = Isleapyear ($nYEAR);  Month $nNM = $nN; if ($nNM > (59 + $NA) {$nNM = $nNM + 2-$nA;  } $nNM = $nNM + 91;  $nMONTH = P (* $nNM, 611)-2;  Day $nNT = $nN;  $nNT = $nN;  if ($nNT > ($nA)) {$nNT = $nNT + 2-$nA;  } $nNT = $nNT + 91;  $nM = P (* $nNT, 611);  $nDAY = $nNT-P (611 * $nM, 20); $dtEasterSunday = Mktime (0,0,0, $nMONTH, $nDAY, $nYEAR); } return $dtEasterSunday;}? >

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