Php in_array syntax

Source: Internet
Author: User
Tags comparison php tutorial

Var_dump (in_array (0, array ('s '));

The result of this statement is bool (true ).

Because in_array compares 0 and 'S', 0 is the number type, and 'S' is the string type. According to the instructions in chapter "comparison operators" in the manual of the php Tutorial, number and string

During comparison, the string type is first converted to number before comparison. The result of converting 's' to number is 0, and the result of 0 = 0 is true, so in_array (0, array ('s', 'SS ')) the result is true.

If the third parameter strict of in_array is set to true, the system checks whether the value and type are equal during comparison. True is returned only when the values are equal. Otherwise, false is returned.

About phpIn_arraySyntax

<? Php
$ A = array ('1', 12.4, 1.13 );

If (in_array ('12. 4', $ a, true )){
Echo "'12. 4' found with strict checkn ";
}

If (in_array (1.13, $ a, true )){
Echo "1.13 found with strict checkn ";
}
?>

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