PHP Query Statement SELECT COUNT (*) from table where type= ' literary life ' how to output results

PHP Query Statement SELECT COUNT (*) from table where type= ' literary life '; How to output a result
$sql = "SELECT count (*) from table where type= ' literary life ';
$result =mysql_query ($sql);
while ($row =mysql_fetch_array ($result)) {
?>
??
}
?>
Do not know how to write the output of this piece, how to write
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    $sql = "SELECT count (*) as ' cnt ' from table where type= ' literary life ';
    $result =mysql_query ($sql);
if ($row =mysql_fetch_array ($result)) {
?>
     
 
 
   
 
     }

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Change Count (*) to *
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or this:

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