PHP Strtotime calculates the last one months of today's problem solving _php tutorial

Today's small series to introduce you to a PHP strtotime calculation on the one months of today's problem resolution, if you hit the calculation for one months today there is a problem not to enter the reference.

PHP, last one months

Strtotime has a little problem.

The code is as follows	Copy Code
> php-r "echo Date (' Ymd000000′,strtotime ('-1 month ', Strtotime (' 201307310000′)"); 20130701000000# > php-r "echo Date (' Ymd000000′,strtotime ('-1 month ', Strtotime (' 201308010000′)"); 20130701000000#

Search for a bit, the following method is more accurate

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$time = Strtotime ("2011-03-31");

The function mktime, which can get the timestamp of the date:

int mktime ([int $hour [, int $minute [, int $second [, int $month [, int $day [, int $year [, int $is _DST]] []]

Returns the Unix timestamp based on the given parameters. The timestamp is a long integer containing the number of seconds from the Unix era (January 1 1970 00:00:00 GMT) to a given time.

Parameters can be omitted from right to left, and any omitted parameters are set to the current value of the cost date and time.
So it can be used to calculate

The code is as follows	Copy Code
function Last_month_day ($time) { $strtime =mktime (Date (' H ', $time), date (' I ', $time), date (' s ', $time), date (' m ', $time) -1,date (' d ', $time), date (' Y ', $ Time)); echo Date (' y-m-d ', $strtime); } Last_month_day (Strtotime ("2012-03-31"));

The result of the output is 2012-03-02; it should be the output 2012-02-31???? Idiot, did you have number 31st in February? No. 30th, no? Is there a number 29th??.. This one.. can have ...
PHP has dealt with this situation for us, and he will do it for a few more days by next month.
February 2012 The last day is 2012-02-29 then 31st is more than 29 two days, so PHP added to the next month to deal with is 2012-03-02.
Almost forgot. How about the day of the week?? Don't count it. PHP is ready for us.
Date (' W ', $strtime); The first day of the week.

Example

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/** * Calculated for the previous one months today, if not today, then return to the last day of one months * @param type $time * @return Type */ Function Last_month_today ($time) { $last _month_time = mktime (date ("G", $time), date ("I", $time), Date ("s", $time), date ("n", $time), 0, date ("Y", $time)); $last _month_t = date ("T", $last _month_time); If ($last _month_t < date ("J", $time) { Return date ("Y-m-t h:i:s", $last _month_time); } Return Date (date ("Y-m", $last _month_time). "-D", $time); } Echo last_month_today ($time);

http://www.bkjia.com/PHPjc/633186.html www.bkjia.com true http://www.bkjia.com/PHPjc/633186.html techarticle today's small series to introduce you to a PHP strtotime calculation on the one months of today's problem resolution, if you hit the calculation for one months today there is a problem not to enter the reference. PHP, last one months ...

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