Php Why array ()! = 0

Array () false0false & #039; & #039; false0 & #039; & #039; but the question is why array ()! 0 array ()! & #039; & #039; array () = false
0 = false
''= False
0 =''
But the problem arises.
Why?
Array ()! = 0
Array ()! =''

Reply content:

Array () = false
0 = false
''= False
0 =''
But the problem arises.
Why?
Array ()! = 0
Array ()! =''

From: http://php.net/manual/zh/types.comparisons.php

The comparison result is related to the internal mechanism of php. It doesn't matter if you cannot understand it now. Just remember it as a rule.

Array ()! = 0
Array ()! =''

Arrays cannot be directly compared with int or string types.

Who told you=And! =The two operators are passed. Both 1 and 2 are = true. Is 1 equal to 2?