PHP's most basic ++a and a++ increments

PHP increment

$a = 3;
echo $a + +. '
';//3
echo + + $a; 5
?>
A++ is the first to add
++a is first added and then Fu

Who can tell me one step at a time, and I'll give it to him at once.

Reply to discussion (solution)

echo $a + + equals: echo $a; $a + = 1;
echo + + $a equivalent to: $a + = 1;echo $a;

In other words: $a + + is the first to use the variable value, after the self-increment
+ + $a is the first self-increment variable value, after use.

Can I make an analogy?
Other words
$a =1
Echo $a + +//meaning 1++??? equals 1
echo $++a//++1++ equals 3

Can I make an analogy?
Other words
$a =1
Echo $a + +//meaning 1++??? equals 1
echo $++a//++1++ equals 3

You finally understand is wrong, the first two steps after the execution, $a is equal to 2, so the final step is directly ++1, there will not be a + +
Look at the following example

!--? php $a = 1;echo $a + +;//output 1 output $ A before performing $a++, so the following echo $a is 2echo $a;//Output 2//  2echo + + $a;//output 3 + + $a, first perform the + + operation, that is 3, and then output $ A  
 
 
 echo $a + +;  
 equivalent to: 
 Echo $a;  
 $a = $a + 1;  
 
 Echo + + $a;  
 equivalent to: 
 $a = $a + 1; 
 Echo $a; 
   
 
 
!--? php $a = 3; echo $a + +. '   
   
     ';    The above sentence can be broken into echo $a,//3 output $a +1;//and then $a=4//echo + + $a; The above sentence can be split into $a +1;//first operation $a=4 plus 1 to get 5 echo $a;//5 again output? 
   
 
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