Fence repair
Time limit:2000 ms |
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Memory limit:65536 K |
Total submissions:27043 |
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Accepted:8792 |
Description
Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needsN(1 ≤N≤ 20,000) planks of wood, each having some integer LengthLi(1 ≤Li≤ 50,000) units. He then purchases a single long board just long enough to saw intoNPlanks (I. e., whose length is the sum of the lengthsLi). Fj is ignoring the "kerf", the extra length lost to sawdust when a sawcut is made; You shoshould ignore it, too.
FJ sadly realizes that he doesn't own a saw with which to cut the wood, so he mosies over to farmer don's farm with this long board and politely asks if he may borrow a saw.
Farmer Don, a closet capitalist, doesn't lend FJ a saw but instead offers to charge Farmer John for each ofN-1 cuts in the plank. The charge to cut a piece of wood is exactly equal to its length. Cutting a plank of length 21 costs 21 cents.
Farmer Don then lets farmer john decide the order and locations to cut the plank. Help Farmer John determine the minimum amount of money he can spend to createNPlanks. fj knows that he can cut the board in varous different orders which will result in different charges since the resulting intermediate planks are of different lengths.
Input
Line 1: One integer
N, The number of planks
Lines 2 ..
N+ 1: each line contains a single integer describing the length of a needed plank
Output
Line 1: One INTEGER: the minimum amount of money he must spend to make
N-1 cuts
Sample Input
3858
Sample output
34
Hint
He wants to cut a board of length 21 into pieces of lengths 8, 5, and 8.
The original Board measures 8 + 5 + 8 = 21. the first cut will cost 21, and shoshould be used to cut the Board into pieces measuring 13 and 8. the second cut will cost 13, and shoshould be used to cut the 13 into 8 and 5. this wocould cost 21 + 13 = 34. if the 21 was cut into 16 and 5 instead, the second cut wocould cost 16 for a total of 37 (which is more than 34 ).
Question: The minimum cost of splitting a wooden board into the following one is as follows;
Solution: First, find the two smallest boards, merge the two Boards, and add the new boards to the boards. Then, find the two smallest boards, continue to merge them, and put them in, and then... Until only one piece of wood is left;
#include <iostream>#include <queue>using namespace std;typedef long long ll;#define MAX_N 20000+5int N,L[MAX_N];void solve(){ll ans=0;priority_queue< int, vector<int> , greater<int> > que;for (int i=0;i<N;i++)que.push(L[i]);while (que.size()>1){int l1,l2;l1=que.top();que.pop();l2=que.top();que.pop();ans+=l1+l2;que.push(l1+l2);}cout<<ans<<endl;}int main(){while (cin>>N){for (int i=0;i<N;i++)cin>>L[i];solve();}return 0;}
Poj 3253 fence repair